在Google Analytics(分析)中,如何从AccountEntry获取网站?

看起来像这样,如果我这样做:


entry.getProperty(“ ga:accountName”)
entry.getTitle()。getPlainText()


我知道了。但这是正确的吗?
它在哪里记录?

最佳答案

看一下XML account feed reference以及从API返回的所有数据。
Here一个访问所有重要帐户供稿信息的Java示例:

for (AccountEntry entry : accountFeed.getEntries()) {
    System.out.println(
      "\nWeb Property Id = " + entry.getProperty("ga:webPropertyId") +
      "\nAccount Name    = " + entry.getProperty("ga:accountName") +
      "\nAccount ID      = " + entry.getProperty("ga:accountId") +
      "\nProfile Name    = " + entry.getTitle().getPlainText() +
      "\nProfile ID      = " + entry.getProperty("ga:profileId") +
      "\nTable Id        = " + entry.getTableId().getValue() +
      "\nCurrency        = " + entry.getProperty("ga:currency") +
      "\nTimeZone        = " + entry.getProperty("ga:timezone") +
      (entry.hasCustomVariables() ? "\nThis profile has custom variables" : "") +
      (entry.hasGoals() ? "\nThis profile has goals" : ""));
  }


这是一个示例结果:

Web Property Id = UA-4276604-4
Account Name    = www.mainsite.net
Account ID      = 4246204
Profile Name    = www.systempuntoout.com
Profile ID      = 26084768
Table Id        = ga:26084768
Currency        = USD
TimeZone        = Europe/Rome


使用以下代码按要求获取网站:

entry.getTitle().getPlainText()

09-25 22:04