React提示下面的代码,说它的useEffect被有条件地调用:
import React, { useEffect, useState } from 'react'
import VerifiedUserOutlined from '@material-ui/icons/VerifiedUserOutlined'
import withStyles from '@material-ui/core/styles/withStyles'
import firebase from '../firebase'
import { withRouter } from 'react-router-dom'
function Dashboard(props) {
const { classes } = props
const [quote, setQuote] = useState('')
if(!firebase.getCurrentUsername()) {
// not logged in
alert('Please login first')
props.history.replace('/login')
return null
}
useEffect(() => {
firebase.getCurrentUserQuote().then(setQuote)
})
return (
<main>
// some code here
</main>
)
async function logout() {
await firebase.logout()
props.history.push('/')
}
}
export default withRouter(withStyles(styles)(Dashboard))
然后返回错误:
Line 48: React Hook "useEffect" is called conditionally. React Hooks must be called in the exact same order in every component render react-hooks/rules-of-hooks
有谁碰巧知道这里的问题是什么?
最佳答案
在包含if
的return
语句之后,您的代码等效于else
分支:
if(!firebase.getCurrentUsername()) {
...
return null
} else {
useEffect(...)
...
}
这意味着它是有条件执行的(仅当不执行return
时)。修理:
useEffect(() => {
if(firebase.getCurrentUsername()) {
firebase.getCurrentUserQuote().then(setQuote)
}
}, [firebase.getCurrentUsername(), firebase.getCurrentUserQuote()])
if(!firebase.getCurrentUsername()) {
...
return null
}