我目前有一个网页,该网页使用执行以下操作的JavaScript:
function callSomething(parm) {
req = false;
if (window.XMLHttpRequest) {
try {
req = new XMLHttpRequest();
} catch (e) {
req = false;
}
} else if (window.ActiveXObject) {
try {
req = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
req = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {
req = false;
}
}
}
if (req) {
var url_str = "/Servlet?parm=" + parm;
req.open("GET", url_str, false);
req.onreadystatechange = processReqChange;
req.send(null);
// process the response
}
return something;
}
我担心的是,如果有人在浏览器窗口中手动输入完整的URL(例如“ http://somesampleserver.com/Servlet?parm=something”),也会显示响应。如何防止这种情况发生?我只希望代码能够获得响应。
最佳答案
听起来您想检查这是否是XHR请求。您可以检查X-Requested-With标头
Boolean isXHR = "XMLHttpRequest".equals(request.getHeader("X-Requested-With"));
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