php - PHP代码每次运行都会降低EC2

我为我的PHP代码设置了一个Cron作业，使其每20分钟运行一次。
但是它每次都会杀死EC2 t2micro实例。这是服务器日志。
请帮助。


  ip-172-31-42-52登录：[20332.164336]内存不足：杀死进程1241（java）得分174或牺牲孩子
      [20332.192538]已杀死进程1241（java）total-vm：1473180kB，anon-rss：176012kB，file-rss：0kB
      [23932.654770]内存不足：杀死进程1131（mysqld）得分71或牺牲孩子
      [23932.690310]杀死进程1131（mysqld）total-vm：908644kB，anon-rss：72004kB，file-rss：0kB
      [39839.833448]内存不足：杀死进程4616（mysqld）得分68或牺牲孩子
      [39839.845119]杀死了进程4616（mysqld）total-vm：908692kB，anon-rss：68816kB，file-rss：0kB
      [39839.901289]内存不足：杀死进程4646（mysqld）得分69或牺牲孩子
      [39839.937446]已杀死进程4646（mysqld）total-vm：908692kB，anon-rss：70392kB，file-rss：0kB
      [63862.861894]内存不足：杀死进程6802（mysqld）得分66或牺牲孩子
      [63862.875681]终止进程6802（mysqld）total-vm：908176kB，anon-rss：66820kB，file-rss：0kB
      [134458.272131] end_request：I / O错误，开发xvda，扇区627665
      [134458.288710] end_request：I / O错误，开发xvda，扇区627681
      [134458.298582] end_request：I / O错误，开发xvda，扇区5577385
      [134458.301842] end_request：I / O错误，开发xvda，扇区5577401
      [134458.302578] end_request：I / O错误，开发xvda，扇区5577425
      [134458.302578] end_request：I / O错误，开发xvda，扇区5544705
      [134458.302578] end_request：I / O错误，开发xvda，扇区1890769
      [134458.302578] end_request：I / O错误，开发xvda，扇区1889537
      [134458.302578] end_request：I / O错误，开发xvda，扇区1889601
      [134458.302578] end_request：I / O错误，开发xvda，扇区1889657


这是PHP代码

<?php

$cf = dirname(__FILE__);
if ($cf) chdir($cf);

include_once('/var/www/html/clubberi.com/includes/incl.php');
$conn = ConnectToDatabese();
$ADODB_FETCH_MODE = ADODB_FETCH_ASSOC;

include_once('/var/www/html/clubberi.com/adm/cklog.php');

include_once('/var/www/html/clubberi.com/cls/trights.php');
global $rights;
$rights = new TRights();
$rights->conn = $conn;
$rights->Init();

$update_gallery="INSERT INTO GALLERY (NAZ,SCIMG,SCHEDULE,IUSER) VALUES ";

$sql="SELECT ID,NAZ,INSTA_LINK FROM PLACE WHERE INSTA_LINK<>'' AND GENRE=416";
$rs=$conn->Execute($sql) or die("Ошибка выполнения $sql");

set_time_limit(240);
    $i=0;
$link = "";
while(!$rs->EOF)
{
    $SCHEDULE = GetFieldFromSQL($conn,"SELECT ID FROM SCHEDULE WHERE DATE(ACTIONTIME)=CURDATE() AND PLACE=".$rs->fields['ID'] ,0);
    if(!$SCHEDULE){
        $MAX_SC_ID = GetFieldFromSQL($conn,"SELECT MAX(ID) FROM SCHEDULE" ,0);
        $curid = $MAX_SC_ID+1;
        $nos = NewObject($conn,'TSchedule',$curid);
        $nos->sf('NAZ','Some party - '.date('d.m.Y'));
        $nos->sf('PLACE',$rs->fields['ID']);
        $nos->sf('ACTIONTIME',date('d.m.Y'));
        $s = $nos->BaseInsert();
        $SCHEDULE = $nos->id;
    }
    $jsonurl = "https://api.instagram.com/v1/locations/".$rs->fields['INSTA_LINK']."/media/recent?client_id=421b46699e074734932d59771fcd1daf";
        #echo $jsonurl;
        $newUrl = htmlspecialchars_decode($jsonurl);
        $json = file_get_contents($newUrl, 0, null, null);
        #print_r("<br>".strlen($json));
        $json_output = json_decode($json, true);

    while(isset($json_output['data'][$i]['images']['standard_resolution']))
    {
            $CUR_IMG = GetFieldFromSQL($conn,"SELECT ID FROM GALLERY WHERE SCIMG=".sqlstr($json_output['data'][$i]['images']['standard_resolution']['url']) ,0);
            if(!$CUR_IMG)
            {
                $update_gallery.="('image-".$i."',".sqlstr(hsc($json_output['data'][$i]['images']['standard_resolution']['url'])).",".$SCHEDULE.",".sqlstr($json_output['data'][0]['caption']['from']['id'])."),";
                $i++;
            }
    }
    $rs->MoveNext();
}

if($i){
    $update_gallery = substr($update_gallery, 0, (strlen($update_gallery)-1));
    $rs=$conn->Execute($update_gallery) or die("Ошибка выполнения $update_gallery");
    echo $i."images";
}else echo "no image ";

?>

最佳答案

是否有可能永远不会退出while循环的“ standard_resolution”？如果$CUR_IMG为TRUE，则$i永远不会递增。因此它将永远停留在该循环中！