我正在JSPsych中编写一个实验，其中有10个条件。我需要根据情况呈现由五个具有不同频率的图像组成的阵列。
我已经设法使用for循环和randomize.sampleWithReplacement进行某种工作，但是它没有以我需要的频率显示图像。
例如，在一种情况下，我希望图像5被呈现8次，图像4被呈现6次，依此类推。
有谁知道我如何使用插件和JSPsych函数实现这一目标？
到目前为止，这是我的代码：
if (cond2 == 'uniform') {
var ratings_r = jsPsych.randomization.repeat(ratings, 4);
for (var i = 0; i < ratings_r.length; i++) {
timeline.push({
type: "html-button-response",
choices: ['Click here to continue'],
button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
is_html: true,
timeline: [{
stimulus: "<img src=" + ratings_r[i] + "><br><br><br>"
}
]
});
}
} if (cond2 == 'left-skew') {
var ratings_ls = jsPsych.randomization.sampleWithReplacement(ratings, 20, [2, 1, 1, 1, 1]);
console.log(ratings_ls)
for (var i = 0; i < ratings_ls.length; i++) {
timeline.push({
type: "html-button-response",
choices: ['Click here to continue'],
button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
is_html: true,
timeline: [{
stimulus: "<img src=" + ratings_ls[i] + "><br><br><br>"
}
]
});
}
} else {
var ratings_rs = jsPsych.randomization.sampleWithReplacement(ratings, 20, [1, 1, 1, 1, 4]);
console.log(ratings_rs)
for (var i = 0; i < ratings_rs.length; i++) {
timeline.push({
type: "html-button-response",
choices: ['Click here to continue'],
button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
is_html: true,
timeline: [{
stimulus: "<img src=" + ratings_rs[i] + "><br><br><br>"
}
]
});
}
};
它适用于第一个条件（因为这很简单）。
这只是我用JSPsych编写的第二个实验，因此我是一个新手，将不胜感激！
------------------更新--------------
我现在有这个：
if (cond2 == 'uniform') {
var uni = jsPsych.randomization.sampleWithoutReplacement([5, 5, 5, 5, 4, 4, 4, 4, 3, 3, 3, 3, 2, 2, 2, 2, 1, 1, 1, 1]);
console.log(uni);
for (var i = 0; i < uni.length; i++) {
timeline.push({
type: "html-button-response",
choices: ['Click here to continue'],
button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
is_html: true,
timeline: [{
stimulus: "<img src=" + ratings[i] + "><br><br><br>"
}
]
});
}
} else if (cond2 == 'left-skew') {
var lesk = jsPsych.randomization.sampleWithoutReplacement([5, 5, 5, 5, 5, 5, 5, 5, 4, 4, 4, 4, 4, 4, 3, 3, 3, 2, 2, 1]);
console.log(lesk);
for (var i = 0; i < lesk.length; i++) {
timeline.push({
type: "html-button-response",
choices: ['Click here to continue'],
button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
is_html: true,
timeline: [{
stimulus: "<img src=" + ratings[i] + "><br><br><br>"
}
]
});
}
} else {
var risk = jsPsych.randomization.sampleWithoutReplacement([1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 5]);
console.log(risk);
for (var i = 0; i < risk.length; i++) {
timeline.push({
type: "html-button-response",
choices: ['Click here to continue'],
button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
is_html: true,
timeline: [{
stimulus: "<img src=" + ratings[i] + "><br><br><br>"
}
]
});
}
};
我创建了一个随机排列的数组，该数组规定了演示频率，但是我不确定如何将其合并到循环中，以使图像呈现该次数。图像分别标记为1,2,3,4,5。
最佳答案
终于找到了可行的方法。
if (cond2 == 'uniform') {
var uni = jsPsych.randomization.sampleWithoutReplacement([5, 5, 5, 5, 4, 4, 4, 4, 3, 3, 3, 3, 2, 2, 2, 2, 1, 1, 1, 1], 20);
console.log(uni);
for (var i = 0; i < uni.length; i++) {
timeline.push({
type: "html-button-response",
choices: ['Click here to continue'],
button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
is_html: true,
timeline: [{
stimulus: "<img src=./img/" + uni[i] + ".png><br><br><br>"
}
]
});
}
} else if (cond2 == 'left_skew') {
var lesk = jsPsych.randomization.sampleWithoutReplacement([5, 5, 5, 5, 5, 5, 5, 5, 4, 4, 4, 4, 4, 4, 3, 3, 3, 2, 2, 1], 20);
console.log(lesk);
for (var i = 0; i < lesk.length; i++) {
timeline.push({
type: "html-button-response",
choices: ['Click here to continue'],
button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
is_html: true,
timeline: [{
stimulus: "<img src=./img/" + lesk[i] + ".png><br><br><br>"
}
]
});
}
} else {
var risk = jsPsych.randomization.sampleWithoutReplacement([1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 5], 20);
console.log(risk);
for (var i = 0; i < risk.length; i++) {
timeline.push({
type: "html-button-response",
choices: ['Click here to continue'],
button_html: '<button class="jspsych-btn" style="display:none">%choice%</button>',
on_start: function() { setTimeout(function(){setDisplay("jspsych-btn","")}, 3000)},
is_html: true,
timeline: [{
stimulus: "<img src=./img/" + risk[i] + ".png><br><br><br>"
}
]
});
}
};
So I basically created an array specifying the frequency for each condition and called that in the for loop.