我想将主持人的第一个加入会议的人设置为主持人,我正在使用twilio-python doc来帮助我,但我对此一无所获。

第一位参与者应该是主持人,以便让另一个人静音,踢脚等,但老实说,我不知道这是否确实需要,所以我愿意接受“不需要主持人”。

我也想知道与令牌相关的名称是否在参与者中,以便以此令牌而不是SID进行检索。 (在文档中看不到任何内容)

这里是服务器端代码:

@app.route('/call', methods=['GET', 'POST'])
def call():
  resp           = twilio.twiml.Response()
  from_value     = request.values.get('From')
  to             = request.values.get('To')
  conferenceName = request.values.get('conferenceName')

  account_sid     = os.environ.get("ACCOUNT_SID", ACCOUNT_SID)
  auth_token      = os.environ.get("AUTH_TOKEN", AUTH_TOKEN)
  app_sid         = os.environ.get("APP_SID", APP_SID)
  clientTwilio  = TwilioRestClient(account_sid, auth_token)

elif to.startswith("conference:"):
    # allows to user conference call
    # client -> conference
    conferencesList = client.conferences.list(friendly_name=conferenceName)

  #there's no conference with the conferenceName so the first person should be the moderator and join it
    if len(conferencesList) == 0
      #do somestuff to set a moderator [...]
      resp.dial(callerId=from_value).conference(to[11:])
    else:
      #there's already a conference just join it
      resp.dial(callerId=from_value).conference(to[11:])


以及与我要用于检索参与者的令牌/客户端相关的“名称”:

     //http://foo.herokuapp.com/token?client=someName"
     self.phone = [[TCDevice alloc] initWithCapabilityToken:token delegate:self];
    NSDictionary *params = @{@"To": @"conference:foo"};
    self.connection = [self.phone connect:params delegate:self];
        [self closeNoddersView:nil];
    //the user is connected as participant in the conference, is it possible to retrieve it with the "someName" ? (server side route which take a "someName" in param)


有什么线索吗? :/

最佳答案

我找到了使用client:name的解决方法,不需要主持人


  会议包含与会者列表
  
  参与者与特定通话有关
  
  呼叫包含to和from_:client:name中的信息


@app.route('/conference_kick', methods=['GET', 'POST'])
    def conference():
      client          = TwilioRestClient(account_sid, auth_token)
      conferenceName  = request.values.get('conferenceName')
      participantName = request.values.get('participantName')
      index           = 0
      call            = ""
      # A list of conference objects
      conferencesList = client.conferences.list(status="in-progress",friendly_name=conferenceName)
      if len(conferencesList) == 1:
        if conferencesList[0].participants:
          participants = conferencesList[0].participants.list()
          while index < len(participants):
            call       = client.calls.get(participants[index].call_sid)
            array = call.from_.split(':')
            if participantName == array[1]:
              participants[index].kick()
              return json.dumps({'code' : 200, 'success':1, 'message':participantName+' kicked'})
            index      += 1
          return json.dumps({'code' : 101, 'success':0, 'message':participantName+' not found'})
        else:
          return json.dumps({'code' : 102, 'success':0, 'message':'no participants'})
      else:
        return json.dumps({'code' : 103, 'success':0, 'message':'no conference'})

关于python - Twilio session 主持人和与会者名称,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/35033259/

10-12 21:24