以下是我的代码文件...
我无法插入图像。错误为，未定义变量：image
<html>
<head>
<title> Upload an image </title>
</head>
<body>
<form action="image-disp.php" method="post" enctype="multipart/form-data">
File:
<input type="file" name="image" value=iamge><br>
<input type="submit" value="Upload">
</form>
<?php
mysql_connect("localhost", "root", " ") or die(mysql_error());
mysql_select_db("mysql") or die(mysql_error());
echo "connected";
if (!isset($_FILES['image'] ['tmp_name'])) {
echo "Choose an image";
} else {
echo $image = addslashes($_FILES['image'] ['tmp_name']);
echo $image_name = addslashes($_FILES['image']['name']);
echo $image_size = getimagesize($_FILES['image'] ['tmp_name']);
}
if ($image_size = FALSE) {
echo "It's not an image";
} else {
$result = "INSERT INTO testblob (image_id, image, image_size) "
. "VALUES (' ' ,'$image', '$image_size')";
}
echo "inserted";
?>
</body>
</html>
最佳答案
最好只将图像名称保存在数据库中，并将文件保存在某个文件夹中
$result = "INSERT INTO testblob ( image, image_size)
VALUES ('$image_name', '$image_size')";
然后您像这样检索它：
<img src="path/<?php echo $row['image_name'];?>">