我想在一个表的“电子邮件ID”列中存储多个“电子邮件ID”作为多值属性。我该如何在oracle中做到这一点?

最佳答案

传统的关系方式是使用子堆表:

create table emails
    (id number
     , email_address varchar2(254)
     , constraint em_t23_fk foreign key (id)
                  references t23 (id)
                  )
/

但是,您暗示了一个嵌套表:
create type email_t as object
    (email_address varchar2(254))
/

create type email_nt as table of email_t
/
alter table t23
    add emails email_nt
    nested table emails store as emails_table
/

运作方式如下:
SQL> update t23
  2  set emails = email_nt (email_t('[email protected]')
  3                          , email_t('[email protected]'))
  4  where id = 222
  5  /

1 row updated.

SQL> select * from t23
  2  where id = 222
  3  /

        ID NAME                           DOB
---------- ------------------------------ ---------
EMAILS(EMAIL_ADDRESS)
----------------------------------------------------------------------------------
       222 Sam-I-Am                       06-AUG-02
EMAIL_NT(EMAIL_T('[email protected]'), EMAIL_T('[email protected]'))


SQL>

编辑

VARRAY的解决方案基本上是相同的:
SQL> alter table t23
  2      drop column emails
  3  /

Table altered.

SQL> create type email_va as varray(5) of varchar2(254)
  2  /

Type created.

SQL> alter table t23
  2      add emails email_va
  3  /

Table altered.

SQL> update t23
  2  set emails = email_va ('[email protected]'
  3                        , '[email protected]')
  4  where id = 222
  5  /

1 row updated.

SQL> select t23.name
  2         , e.*
  3  from t23
  4       , table (t23.emails) e
  5  where t23.id = 222
  6  /

NAME                           COLUMN_VALUE
------------------------------ ---------------------------------
Sam-I-Am                       [email protected]
Sam-I-Am                       [email protected]

SQL>

09-25 19:50