我想在一个表的“电子邮件ID”列中存储多个“电子邮件ID”作为多值属性。我该如何在oracle中做到这一点?
最佳答案
传统的关系方式是使用子堆表:
create table emails
(id number
, email_address varchar2(254)
, constraint em_t23_fk foreign key (id)
references t23 (id)
)
/
但是,您暗示了一个嵌套表:
create type email_t as object
(email_address varchar2(254))
/
create type email_nt as table of email_t
/
alter table t23
add emails email_nt
nested table emails store as emails_table
/
运作方式如下:
SQL> update t23
2 set emails = email_nt (email_t('[email protected]')
3 , email_t('[email protected]'))
4 where id = 222
5 /
1 row updated.
SQL> select * from t23
2 where id = 222
3 /
ID NAME DOB
---------- ------------------------------ ---------
EMAILS(EMAIL_ADDRESS)
----------------------------------------------------------------------------------
222 Sam-I-Am 06-AUG-02
EMAIL_NT(EMAIL_T('[email protected]'), EMAIL_T('[email protected]'))
SQL>
编辑
VARRAY的解决方案基本上是相同的:
SQL> alter table t23
2 drop column emails
3 /
Table altered.
SQL> create type email_va as varray(5) of varchar2(254)
2 /
Type created.
SQL> alter table t23
2 add emails email_va
3 /
Table altered.
SQL> update t23
2 set emails = email_va ('[email protected]'
3 , '[email protected]')
4 where id = 222
5 /
1 row updated.
SQL> select t23.name
2 , e.*
3 from t23
4 , table (t23.emails) e
5 where t23.id = 222
6 /
NAME COLUMN_VALUE
------------------------------ ---------------------------------
Sam-I-Am [email protected]
Sam-I-Am [email protected]
SQL>