我正在尝试过滤我的结果。为此,我有以下查询:
$destinations = $request['destinations'];
if($request->has('destinations'))
{
$trips = Trip::where('status','=',1)->whereHas('destinations', function($q) {
$q->where('destinationsid', '=', $destinations);
})->get();
}else{
echo "No destination provided";
}
但是我得到了 undefined variable $destinations。如果我用任何 id (6) 替换 $destinations,它会显示结果。
我还尝试在查询之外回显 $destinations,它正在返回数组。这里有什么问题?谁能帮我?
最佳答案
尝试在 use($destination)
之后添加 function($q)
:
$destinations = $request['destinations'];
if($request->has('destinations'))
{
$trips = Trip::where('status','=',1)->whereHas('destinations', function($q) use($destinations) {
$q->where('destinationsid', '=', $destinations);
})->get();
} else {
echo "No destination provided";
}
关于php - undefined variable 。 Laravel,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/48740075/