javascript - 用 enzyme 测试重组的HOC

如何测试(使用jest + enzyme)使用recompose创建HoC的以下代码:

import {compose, withState, withHandlers} from 'recompose'

const addCounting = compose(
  withState('counter', 'setCounter', 0),
  withHandlers({
    increment: ({ setCounter }) => () => setCounter(n => n + 1),
    decrement: ({ setCounter }) => () =>  setCounter(n => n - 1),
    reset: ({ setCounter }) => () => setCounter(0)
  })
)

执行浅渲染时，我可以访问counter和setCounter属性，如下所示:

import {shallow} from 'enzyme'

const WithCounting = addCounting(EmptyComponent)
const wrapper = shallow(<WithCounting />)

wrapper.props().setCounter(1)
expect(wrapper.props().counter).toEqual(1)

最大的问题是，如何访问处理程序(increment，decrement和reset)并调用它们？它们没有出现在wrapper.props()中

最佳答案

因此，您可以通过首先找到实例来访问 Prop :

const EmptyComponent = () => null;
const WithCounting = addCounting(props => <EmptyComponent {...props} />);
const wrapper = mount(<WithCounting />);

wrapper.find(EmptyComponent).props().setCounter(1);
expect(wrapper.find(EmptyComponent).props().counter).toEqual(1);