c - 如何在C程序中调用函数？

我正在尝试使用以下规则构建骰子游戏：


你掷三个骰子
如果掷骰子且每个骰子为6，您将赢得100kr
如果掷骰子且每个骰子相同（但不是6个），则赢得50kr
如果掷骰子且两个骰子相同，则赢得10 kr
玩家每轮必须下注至少10kr
如果玩家获胜，询问他们是否要再次玩
当玩家的钱少于10kr时，玩家会被告知他们不能再玩了。


我已经能够做到这一点，但是现在我必须通过调用一个函数来运行它。我现在被卡住了-我的代码在下面，但是我不确定如何继续。

#pragma warning(disable:4996)
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include<stdbool.h>

int rolling(int dice1, int dice2, int dice3, int moneyinput, char keep_rolling ); // prototype
keep_rolling = 'y';

int main()
{
    int d1, d2, d3, money, r;
    char keep_rolling = 'n';
    money = 100;
    r = rolling(d1, d2, d3, money,keep_rolling);
    srand((int)time(NULL));
    printf("welcome to the game! \n \n");

    //gameroll
    printf("1.it cost you 10kr to play \n");
    printf("2.if all the dicies are sixes you win 100kr \n");
    printf("3. if all the dicies are alike except number (6) you win 50kr \n");
    printf("4. if you get at least two alike you 1 \n");
    printf("5. otherwise you win nothing\n");

    printf("you have %d kr, if you wnat to play press (n) \n\n", money);
    fflush(stdin);
    keep_rolling = ((getchar()));
    d1 = (rand() % 6 + 1);
    d2 = (rand() % 6 + 1);
    d3 = (rand() % 6 + 1);


}

int rolling(int dice1, int dice2, int dice3, int moneyinput, char keep_rolling) // def my function
{
    keep_rolling = 'y';
    do {
        dice1 = (rand() % 6 + 1);
        dice2 = (rand() % 6 + 1);// from 1 to 6
        dice3 = (rand() % 6 + 1);

        if (moneyinput < 10)
        {
            printf("you do not have enough money \n");
            break; // exit the program
        }
        moneyinput -= 10;
        if (dice1 == 6 && dice2 == 6 & dice3 == 6)
        {
            printf("you have won 100\n ");
            moneyinput += 90;
        }
        else if (dice1 == dice2 == dice3)
        {
            printf("you have won 50kr \n");
            moneyinput += 40;
        }
        else if (dice1 == dice2 || dice1 == dice3 || dice2 == dice3)
        {
            printf("you have won 10kr \n");
            moneyinput += 10;
        }
        else
        {
            printf("Sorry! you have lost. god luck next time \n");
        }
    } while (keep_rolling == 'y');
    system("pause");
}

最佳答案

您需要将您的问题移至用户的滚动功能。您的主要功能并非独立于滚动功能运行。

另外，如果if语句中存在一些逻辑错误，这些错误会使您的结果与所需的结果有所不同。

if (dice1 == 6 && dice2 == 6 & dice3 == 6)

应该

if (dice1 == 6 && dice2 == 6 && dice3 == 6)

和

else if (dice1 == dice2 == dice3)

应该

else if (dice1 == dice2 && dice2 == dice3)

除此之外，您还需要从滚动功能中获得回报。