docker - Dockerfile中的条件ARG

我有一个Dockerfile，我想根据构建参数来做不同的事情来确定isDev。

在Dockerfile中，我有:

ARG isDev
RUN echo "what is in isDev ? $isDev"
RUN if ["${isDev}" = "1"] ;
     then ..... do dev stuff .... ;
     else .... do production stuff ;
    fi

我正在使用--build-arg isDev = 1进行构建

Step 14/25 : ARG isDev
 ---> Running in 0a3de5fea466
Removing intermediate container 0a3de5fea466
 ---> a6d79a08a97e
Step 15/25 : RUN echo "what is in isDev ? $isDev"
 ---> Running in 92235e8b0c6a
what is in isDev ? 1
Removing intermediate container 92235e8b0c6a
 ---> a7b064687480
Step 16/25 : RUN if ["${isDev}" = "1"] ; then ... do dev stuff ... ; else  ... do production stuff ... ; fi
 ---> Running in bbe6a047705a
[91m/bin/sh: 1: [1: not found

我究竟做错了什么？

最佳答案

您不会喜欢这个答案，在[之后缺少空格。在右括号之前，您将需要另一个空格，并且需要对换行符进行转义。至少这是我乍看之下的内容。

ARG isDev
RUN echo "what is in isDev ? $isDev"
RUN if [ "${isDev}" = "1" ] ; \
     then ..... do dev stuff .... ; \
     else .... do production stuff ; \
    fi