python - 石头，纸，剪刀(python 3.3)

嗨，我正在做一个石头剪子游戏，到目前为止我已经做了以下脚本：

def main():
    from random import randint
    UserChoices = input("'rock', 'paper' or 'scissors'? \n Input: ")
    if UserChoices == "rock":
        UserChoice = 1
    elif UserChoices == "paper":
        UserChoice = 2
    elif UserChoices == "scissors":
        UserChoice = 3
    CpuChoice = randint(1,3)
    if UserChoice == CpuChoice:
        print("DRAW!")
    elif UserChoice == "1" and CpuChoice== "3":
        print("Rock beats scissors PLAYER WINS!")
        main()
    elif UserChoice == "3" and CpuChoice== "1":
        print("Rock beats scissors CPU WINS")
        main()
    elif UserChoice == "1" and CpuChoice== "2":
        print("Paper beats rock CPU WINS!")
        main()
    elif UserChoice == "2" and CpuChoice== "1":
        print("paper beats rock PLAYER WINS!")
        main()
    elif UserChoice == "2" and CpuChoice== "3":
        print("Scissors beats paper CPU WINS!")
        main()
    elif UserChoice == "3" and CpuChoice== "2":
        print("Scissors beats paper PLAYER WINS!")
        main()
    elif UserChoice == "1" and CpuChoice== "2":
        print("cpu wins")
        main()
    else:
        print("Error: outcome not implemented")
main()

但是当我运行它时，我得到了我犯下的错误“错误：结果没有实现”有人能告诉我为什么吗？谢谢您。

最佳答案

这和所有其他类似的比较：

elif UserChoice == "1" and CpuChoice == "3":

... 应该是：

elif UserChoice == 1 and CpuChoice == 3:

换句话说，您应该将ints与ints进行比较，而不是像现在这样将ints与字符串进行比较。

关于python - 石头，纸，剪刀(python 3.3)，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/21732790/