我假设这是一个逻辑错误。我无法将结果相加，也无法获得正确的结果。每次我进入石头，纸张，剪刀时，它都会从那里确定我是赢家，输家还是平手。我的代码有什么问题？
public class RockPaperScissors {
public static void displayGreeting()
{
String intro = "This program is a game. A game of Rock, Paper, Scissors\n"+
"It is you against the computer. Rock beats scissors, Paper\n"+
" beats rock, and scissors beats paper. Good luck and may the\n"+
"odds be ever in your favor.";
JOptionPane.showMessageDialog(null, intro, "Rock Paper Scissors",1);
}
public static String generateComputersChoice()
{
Random randomGenrator = new Random();
int randomNumber = randomGenrator.nextInt(3);
String weapon = "nothing";
switch(randomNumber){
case 0: weapon = "rock";
break;
case 1: weapon = "paper";
break;
case 2: weapon = "scissors";
break;
}
return weapon;
}
public static String enterPlayersChoice(){
String prompt = "You have a choice of picking rock, paper, or scissors.\n"+
"Choose wisely.";
String input = "";
input = JOptionPane.showInputDialog(null,prompt,"Choose your weapon",1);
String inputLower = input.toLowerCase();
return inputLower;
}
public static void main(String[] args)
{
displayGreeting();
// generateComputersChoice();
//enterPlayersChoice();
// JOptionPane.showMessageDialog(null,generateComputersChoice()+ enterPlayersChoice(5));
String player = enterPlayersChoice();
String comp = generateComputersChoice();
int ties = 0;
int playerWins = 0;
int compWins = 0;
for(int i = 0; i < 3; i ++){
//enterPlayersChoice(); //method
//generateComputersChoice(); //method
//JOptionPane.showMessageDialog(null,generateComputersChoice()+ enterPlayersChoice(1));
//System.out.println(player+ " " + comp);
//JOptionPane.showMessageDialog(null,player+ " " +comp);
if(player.equals(comp)){
JOptionPane.showMessageDialog(null, "It's a tie!");
ties ++;
}
else if(player.equals("rock")){
if(comp.equals("scissors")){
JOptionPane.showMessageDialog(null, "You win!");
playerWins ++;
}
}else if(comp.equals("rock")){
if(player.equals("scissors")){
JOptionPane.showMessageDialog(null, "You lose!");
compWins ++;
}
}else if(player.equals("scissors")){
if(comp.equals("paper")){
JOptionPane.showMessageDialog(null, "You win!");
playerWins ++;
}
}else if(comp.equals("scissors")){
if(player.equals("paper")){
JOptionPane.showMessageDialog(null, "You lose");
compWins ++;
}
}else if(player.equals("paper")){
if(comp.equals("rock")){
JOptionPane.showMessageDialog(null, "You Win!");
playerWins ++;
}
}else if(comp.equals("paper")){
if(player.equals("rock")){
JOptionPane.showMessageDialog(null, "You lose!");
compWins ++;
}
}else{
JOptionPane.showMessageDialog(null, "Invalid user input");
i--;
}
}
//Results
JOptionPane.showMessageDialog(null,"Here are the results\n\n"+
"\nTies: " +ties+
"\nComputer Wins: " +compWins+
"\nPlayer Wins: " + playerWins+
"\n\n Program Terminating", "Results",1);
}
}
最佳答案
然后决定我是赢了，被绑还是输了，但不会
之后“重申”。之后，它只是说我要么赢了，要么输了，
或连续绑3次
您实际上在做的是一次询问输入，然后运行循环，因此很显然，您将获得3次相同的结果。
您需要在每次迭代中询问用户输入：
String player;
String comp;
int ties = 0;
int playerWins = 0;
int compWins = 0;
for(int i = 0; i < 3; i ++){
player = enterPlayersChoice();
comp = generateComputersChoice();
/**/
}
关于java - 剪刀石头布。 Java。方法，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/19960797/