System.Web.Security.Membership.GeneratePassword
(AspNetCore
)中的netcoreapp1.0
是否有替代方案。
最简单的方法是只使用一个Guid.NewGuid().ToString("n")
,它足够长,值得输入密码,但它不是完全随机的。
最佳答案
这是一个类/方法,基于在.NET Core上工作的 Membership.GeneratePassword
的来源:
public static class Password
{
private static readonly char[] Punctuations = "!@#$%^&*()_-+=[{]};:>|./?".ToCharArray();
public static string Generate(int length, int numberOfNonAlphanumericCharacters)
{
if (length < 1 || length > 128)
{
throw new ArgumentException(nameof(length));
}
if (numberOfNonAlphanumericCharacters > length || numberOfNonAlphanumericCharacters < 0)
{
throw new ArgumentException(nameof(numberOfNonAlphanumericCharacters));
}
using (var rng = RandomNumberGenerator.Create())
{
var byteBuffer = new byte[length];
rng.GetBytes(byteBuffer);
var count = 0;
var characterBuffer = new char[length];
for (var iter = 0; iter < length; iter++)
{
var i = byteBuffer[iter] % 87;
if (i < 10)
{
characterBuffer[iter] = (char)('0' + i);
}
else if (i < 36)
{
characterBuffer[iter] = (char)('A' + i - 10);
}
else if (i < 62)
{
characterBuffer[iter] = (char)('a' + i - 36);
}
else
{
characterBuffer[iter] = Punctuations[i - 62];
count++;
}
}
if (count >= numberOfNonAlphanumericCharacters)
{
return new string(characterBuffer);
}
int j;
var rand = new Random();
for (j = 0; j < numberOfNonAlphanumericCharacters - count; j++)
{
int k;
do
{
k = rand.Next(0, length);
}
while (!char.IsLetterOrDigit(characterBuffer[k]));
characterBuffer[k] = Punctuations[rand.Next(0, Punctuations.Length)];
}
return new string(characterBuffer);
}
}
}
我在
do...while
上省略了CrossSiteScriptingValidation.IsDangerousString
循环。如果需要,可以将其添加回自己。您可以这样使用它:
var password = Password.Generate(32, 12);
另外,请确保您引用
"System.Security.Cryptography.Algorithms": "4.2.0"
。