我在测试python的继承性,我得到了:

__metaclass__=type
class b:
    def __init__(s):
        s.hungry=True
    def eat(s):
        if(s.hungry):
            print "I'm hungry"
        else:
            print "I'm not hungry"
class d(b):
    def __init__(s):
        super(b,s).__init__()
    def __mysec__(s):
        print "secret!"

obj=d()
obj.eat()

运行时错误为:
Traceback (most recent call last):
  File "2.py", line 17, in ?
    obj.eat()
  File "2.py", line 6, in eat
    if(s.hungry):
AttributeError: 'd' object has no attribute 'hungry'

我无法理解这一点,因为“b”的超类在其in I t中有s.hungry,而子类在其自身的init中调用“super”
为什么python仍然说“d”对象没有“hungry”属性?
另一个困惑是:错误消息将“d”视为一个对象,但我将其定义为一个类!
我做错什么了吗,怎么做?

最佳答案

class d(b):
    def __init__(s):
        super(d,s).__init__()
    def __mysec__(s):
        print ("secret!")

Document
对于这两种用例,典型的超类调用如下所示:
> class C(B):
>     def method(self, arg):
>         super(C, self).method(arg)

09-25 16:35