android - JSON对象解析错误

我有以下字符串作为HTTPResponse。它是JSON格式。

  [
    {
       "From":"en",
       "OriginalTextSentenceLengths":[
          5
       ],
       "TranslatedText":"Hallo",
       "TranslatedTextSentenceLengths":[
          5
       ]
    },
    {
       "From":"en",
       "OriginalTextSentenceLengths":[
          8
       ],
       "TranslatedText":"Frage",
       "TranslatedTextSentenceLengths":[
          5
       ]
   },
   {
       "From":"en",
       "OriginalTextSentenceLengths":[
          6
       ],
       "TranslatedText":"Antwort",
       "TranslatedTextSentenceLengths":[
          7
       ]
  }
]

因此，我按如下方式解析此字符串，以获得“翻译文本数组”

  String resp = "[{\"From\":\"en\",\"OriginalTextSentenceLengths\":[5],\"TranslatedText\":\"Hallo\",\"TranslatedTextSentenceLengths\":[5]},{\"From\":\"en\",\"OriginalTextSentenceLengths\":[8],\"TranslatedText\":\"Frage\",\"TranslatedTextSentenceLengths\":[5]},{\"From\":\"en\",\"OriginalTextSentenceLengths\":[6],\"TranslatedText\":\"Antwort\",\"TranslatedTextSentenceLengths\":[7]}]";

    String[] stringArray = null;
    try {
    JSONArray finalResult=null;
    JSONTokener tokener = new JSONTokener(resp);

        finalResult = new JSONArray(tokener);
        stringArray = new String[finalResult.length()];

    for(int i=0;i<finalResult.length();i++){
        JSONObject e = finalResult.getJSONObject(i);
        Log.v("TAG",e.getString("TranslatedText"));
        stringArray[i]=e.getString("TranslatedText");
    }

    }catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

我正在从JSON对象中获取提取的“翻译后的文本”数组（Hallo，Frage，Antwort）...

但是，当我通过直接向JSONTokener输入相同的字符串作为输入来执行相同的过程时，即在获得如下所示的HttpResponse之后，我在finalResult = new JSONArray（tokener）行中获取了JSON异常....

org.json.JSONException：输入的结尾（字符为0）

String resp = getHttpResponse(uri);
String[] stringArray = null;
    try {
    JSONArray finalResult=null;
    JSONTokener tokener = new JSONTokener(resp);

        finalResult = new JSONArray(tokener);
        stringArray = new String[finalResult.length()];

    for(int i=0;i<finalResult.length();i++){
        JSONObject e = finalResult.getJSONObject(i);
        Log.v("TAG",e.getString("TranslatedText"));
        stringArray[i]=e.getString("TranslatedText");
    }

    }catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

我已经尝试了2天，但无法解决此错误。.所以我将其发布在这里...请帮助

编辑：

我正在添加getHttpResponse的实现

 public static String getHttpResponse(URI uri) {
    Log.d("APP_TAG", "Going to make a get request");
    StringBuilder response = new StringBuilder();
    try {
        HttpGet get = new HttpGet();
        get.setURI(uri);
        //DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpParams httpParameters = new BasicHttpParams();
        int timeoutConnection = 30000;
        HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
        int timeoutSocket = 30000;
        HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);

        DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);

        Log.v("TAG","1");
        HttpResponse httpResponse = httpClient.execute(get);
        Log.v("TAG","2");
        if (httpResponse.getStatusLine().getStatusCode() == 200) {
            Log.d("demo", "HTTP Get succeeded");

            HttpEntity messageEntity = httpResponse.getEntity();
            InputStream is = messageEntity.getContent();
            BufferedReader br = new BufferedReader(new InputStreamReader(is));
            String line;
            while ((line = br.readLine()) != null) {
                response.append(line);
            }
        }
    } catch (Exception e) {
        Log.e("demo", e.getMessage());
    }
    Log.d("demo", "Done with HTTP getting");
    return response.toString();
}

我给getHttpResponse的uri如下

   String[] texts = {"hello","question","answer"};
   final String params = "appId=" +   URLEncoder.encode("78280AF4DFA1CE1676AFE86340C690023A5AC139","UTF-8")
            + "&from=" + URLEncoder.encode("en","UTF-8")
            + "&to=" + URLEncoder.encode("de","UTF-8")
            + "&texts=" +   URLEncoder.encode(buildStringArrayParam(texts),"UTF-8");

     final URL url = new  URL("http://api.microsofttranslator.com/V2/Ajax.svc/TranslateArray?" + params);

     URI myURI = java.net.URI.create(url.toString());
     String resp = getHttpResponse(myURI);

此响应字符串是我要解析的内容...

这是针对buildStringArrayParam（texts）

StringBuilder targetString = new StringBuilder("[\"");
    String value;
    for(Object obj : values) {
        if(obj!=null) {
            value = obj.toString();
            if(value.length()!=0) {
                if(targetString.length()>2)
                    targetString.append(",\"");
                targetString.append(value);
                targetString.append("\"");
            }
        }
    }
    targetString.append("]");
    return targetString.toString();

最佳答案

啊哈...微软。

至少在这种情况下，它们在开始时使用（错误？）FEFF FEFF UTF-16 byte order mark来提供其API响应，这会破坏大多数客户端。

像the PHP guys over here already found out一样，您只需要从响应中除去前两个字节。对于代码中的示例：

JSONTokener tokener = new JSONTokener(resp.substring(2));

恐怕更无害的trim()不起作用。

真的很难找到，因为FEFF的正式名称是“零宽度不间断空格”，因此它是完全不可见的，除非您将字符串视为char数组，或者注意到当您使用左/右箭头键...

请注意，您不应使用收到的任何其他HTTP响应来执行此操作，这仅适用于此Microsoft API（也可以是其他API）。