我有一个HTML表,格式如下:
<table>
<tbody>
<tr>
<td>Book1</td>
<td>Group1</td>
<td>Code1</td>
<td>Lesson1</td>
<td>Day1</td>
<td>Day2</td>
<td>Day3</td>
</tr>
<tr>
<td>Book2</td>
<td>Group2</td>
<td>Code2</td>
<td>Lesson2</td>
<td>Day1</td>
<td>Day2</td>
<td>Day3</td>
</tr>
</tbody>
</table>
我想用jsoup解析这个html,并输出如下格式的json字符串:
{
"Book1": {
"Group": "Group1",
"Code": "Code1",
"Lesson": "Lesson1",
"Day1": "Day1",
"Day2": "Day2",
"Day3": "Day3"
},
"Book2": {
"Group": "Group2",
"Code": "Code2",
"Lesson": "Lesson2",
"Day1": "Day1",
"Day2": "Day2",
"Day3": "Day3"
}
}
我试过这个密码:
public String TableToJson(String source) throws JSONException {
Document doc = Jsoup.parse(source);
JSONObject jsonObject = new JSONObject();
JSONArray list = new JSONArray();
for (Element table : doc.select("table")) {
for (Element row : table.select("tr")) {
Elements tds = row.select("td");
String Name = tds.get(0).text();
String Group = tds.get(1).text();
String Code = tds.get(2).text();
jsonObject.put("Name", Name);
jsonObject.put("Group", Group);
jsonObject.put("Code", Code);
list.put(jsonObject);
}
}
return list.toString();
}
但它返回了错误的结果:
[
{
"Name": "Book1",
"Group": "Group1",
"Code": "Code1"
},
{
"Name": "Book1",
"Group": "Group1",
"Code": "Code1"
}
]
我无法更改表代码,因为它在另一台服务器上。
如何使用java中的jsoup从输入中获得所需的结果?
最佳答案
您的代码的问题是您试图使用相同的jsonObject
,而且您也在使用不需要的JsonArray
。您需要一个包含objects
的对象,而不是包含array of objects
的对象
public String TableToJson(String source) throws JSONException {
Document doc = Jsoup.parse(source);
JSONObject jsonParentObject = new JSONObject();
//JSONArray list = new JSONArray();
for (Element table : doc.select("table")) {
for (Element row : table.select("tr")) {
JSONObject jsonObject = new JSONObject();
Elements tds = row.select("td");
String Name = tds.get(0).text();
String Group = tds.get(1).text();
String Code = tds.get(2).text();
String Lesson = tds.get(3).text();
String Day1 = tds.get(4).text();
String Day2 = tds.get(5).text();
String Day3= tds.get(6).text();
jsonObject.put("Group", Group);
jsonObject.put("Code", Code);
jsonObject.put("Lesson", Lesson);
jsonObject.put("Day1", Day1);
jsonObject.put("Day2", Day2);
jsonObject.put("Day3", Day3);
jsonParentObject.put(Name,jsonObject);
}
}
return jsonParentObject.toString();
}
如果你需要澄清,请告诉我!