是的,之前曾有人问过这个问题。不,我读过的答案都无法解决我遇到的问题。
我正在尝试创建一个小弹跳游戏。我创建了这样的积木:
def __init__(self,canvas):
self.canvas = canvas
self.brick1 = canvas.create_rectangle(0,0,50,20,fill=random_fill_colour(),outline=random_fill_colour())
self.brick2 = canvas.create_rectangle(50,0,100,20,fill=random_fill_colour(),outline=random_fill_colour())
self.brick3 = canvas.create_rectangle(100,0,150,20,fill=random_fill_colour(),outline=random_fill_colour())
self.brick4 = canvas.create_rectangle(150,0,200,20,fill=random_fill_colour(),outline=random_fill_colour())
self.brick5 = canvas.create_rectangle(200,0,250,20,fill=random_fill_colour(),outline=random_fill_colour())
self.brick6 = canvas.create_rectangle(250,0,300,20,fill=random_fill_colour(),outline=random_fill_colour())
self.brick7 = canvas.create_rectangle(300,0,350,20,fill=random_fill_colour(),outline=random_fill_colour())
self.brick8 = canvas.create_rectangle(350,0,400,20,fill=random_fill_colour(),outline=random_fill_colour())
self.brick9 = canvas.create_rectangle(400,0,450,20,fill=random_fill_colour(),outline=random_fill_colour())
self.brick10 = canvas.create_rectangle(450,0,500,20,fill=random_fill_colour(),outline=random_fill_colour())
self.bricksId = [self.brick1,self.brick2,self.brick3,self.brick4,self.brick5,self.brick6,self.brick7,self.brick8,self.brick9,self.brick10]
我正在尝试在此处引用
bricksId[0]
的ID:self.hit_brick(pos,self.bricks.bricksId[0])
之前,在
__init__
中,我将Bricks定义为Bricks,将其定义为Brick(canvas)
。但是,错误指出:TypeError: 'Brick' object does not support indexing
在该主题的其他问题的答案中,我找不到任何可以帮助我访问
bricks.bricksId[0]
的内容。 最佳答案
为了使Brick
对象可索引,必须实现以下方法:
__getitem__
__setitem__
__delitem__
您不需要所有它们,只需要使用那些。
但是,这似乎是
self.bricks
是砖块而不是砖块列表的情况。砖块列表是可索引的;但是,除非您实现上述方法,否则砖块本身不是。检查this以供引用。
为了能够在需要时调用
self.bricks.bricksId[number]
:def __getitem__(self,index):
return self.bricks.bricksId[index]
def __setitem__(self,index,value):
self.bricks.bricksId[index] = value