python - 检查下一行，然后实现该行应该到达的位置

我在弄清楚如何实现文本文件时遇到麻烦，行中既包含单词行又包含数字行。我想尝试做的是读取单词下的行，然后将这些单词保存到列表变量中。

编码新手，请多多包涵。

示例文本文件：

 Hello World
 4, 3, 2
 3, 4, 2
 2, 3, 4
 Change the World
 5, 3, 9
 3, 9, 5
 Save the World
 1, 2, 3

我的伪代码：

 Open File
 Read the First Line
 If the current-line[0] is Letter then:
   parse the current Line
   save the parsed to a Word list
   Go to the next line
 If the current-line[0] is a Number then:
   parse the current Line
   save the parsed line in a list
   read the next line
   If the next line has another number then:
      parse line
      save it to the previous parsed-line list
      #Keep Checking if the next line begins with a number
      #if it doesn't and the next line begins with a letter go back up to the previous statement

我的问题：
    如何告诉python在不离开当前行的情况下检查下一行，然后检查下一行应转到哪个“ if”语句？

示例代码：简体

 def parse():
    return parse

 txtopen = open("txt","r")
 line = txtopen.readline()
 while line:
  if line[0] is not between 0 or 9::
   parse = parse(line)
   wordlist.append(parse)
  if line[0] in between  0 and 9:
   parse = parse(line)
   list = list.extend(parse)
   '''
   This is where i cant figure out how to read the next line and check
   '''
   finallist = list.append(list)
  line = txtopen.readline()

输出：

   wordList : ["Hello Word", "Change the World", "Save the World"]
   numberList : [[4,3,2,3,4,2,2,3,4],[5,3,9,3,9,5],[1,2,3]]

在我的逻辑内使用伪代码提供的任何帮助都将是极好的，或者通常可以提供帮助的任何事情将不胜感激。

最佳答案

要阅读下一行，您可以执行以下操作。

with open("file.txt", 'r') as f:
    lines = f.readlines()
    current_line_index = 0
    next_line = lines[current_line_index + 1]
    print next_line

这是我将如何解决此特定问题的方法。

import csv

word_list = []
number_list = []

with open("file.txt", 'r') as f:
    reader = csv.reader(f)
    for line in reader:
        if line[0].strip().isdigit():
            number_list.append(line)
        else:
            word_list.append(line)

print number_list
print word_list

关于python - 检查下一行，然后实现该行应该到达的位置，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/16005746/