嗨,我正在使用TableStep单元格中的UIStepper。当UIStepper值更改时,我必须在表视图单元格的标签中显示该值。这是代码
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
UILabel *lblQuantityValue = [[UILabel alloc] initWithFrame:CGRectMake(140, 410, 50, 30)];
lblQuantityValue.text = @"1";
lblQuantityValue.tag = indexPath.section;
lblQuantityValue.backgroundColor = [UIColor clearColor];
[[lblQuantityValue layer] setCornerRadius:5];
[[lblQuantityValue layer] setMasksToBounds:YES];
[[lblQuantityValue layer] setBorderWidth:1.0f];
[[lblQuantityValue layer] setBorderColor:[[UIColor orangeColor]CGColor]];
[cell addSubview:lblQuantityValue];
UIStepper *stepper = [[UIStepper alloc] initWithFrame:CGRectMake(200, 410, 50, 30)];
[stepper addTarget:self action:@selector(stepper_ValueChanged:) for ControlEvents:UIControlEventValueChanged];
stepper.tag = indexPath.row;
stepper.minimumValue = 1;
stepper.maximumValue = 10;
[cell addSubview:stepper];
}
stepper_ValueChanged方法如下
-(void)stepper_ValueChanged:(UIStepper*)sender
{
UILabel *lblQuantityValue = (UILabel*)[self.view viewWithTag:sender.tag];
int value2 = [sender value];
lblQuantityValue.text = [NSString stringWithFormat:@"%d", value2];
}
我收到以下崩溃报告
-[UIView setText:]: unrecognized selector sent to instance 0x111e10640
2014-02-26 11:22:24.159 Hyderabad Bazar[2115:a0b] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UIView setText:]: unrecognized selector sent to instance 0x111e10640'
*** First throw call stack:
(
0 CoreFoundation 0x0000000101ce3795 __exceptionPreprocess + 165
1 libobjc.A.dylib 0x00000001019bf991 objc_exception_throw + 43
2 CoreFoundation 0x0000000101d74bad -[NSObject(NSObject) doesNotRecognizeSelector:] + 205
3 CoreFoundation 0x0000000101cd509d ___forwarding___ + 973
4 CoreFoundation 0x0000000101cd4c48 _CF_forwarding_prep_0 + 120
5 Hyderabad Bazar 0x00000001000202a6 -[CartViewController stepper_ValueChanged:] + 390
6 UIKit 0x0000000100628a8a -[UIApplication sendAction:to:from:forEvent:] + 104
7 UIKit 0x0000000100628a20 -[UIApplication sendAction:toTarget:fromSender:forEvent:] + 17
8 UIKit 0x00000001006fc91c -[UIControl _sendActionsForEvents:withEvent:] + 203
9 UIKit 0x0000000100a895d7 -[UIStepper _updateCount:] + 338
10 UIKit 0x0000000100a89346 -[UIStepper endTrackingWithTouch:withEvent:] + 32
11 UIKit 0x00000001006fbe52 -[UIControl touchesEnded:withEvent:] + 472
12 UIKit 0x000000010092cc0d _UIGestureRecognizerUpdate + 5149
13 UIKit 0x000000010065d2e5 -[UIWindow _sendGesturesForEvent:] + 928
14 UIKit 0x000000010065dfa5 -[UIWindow sendEvent:] + 910
15 UIKit 0x0000000100637962 -[UIApplication sendEvent:] + 211
16 UIKit 0x000000010062579f _UIApplicationHandleEventQueue + 9549
17 CoreFoundation 0x0000000101c72e61 __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 17
18 CoreFoundation 0x0000000101c72732 __CFRunLoopDoSources0 + 242
19 CoreFoundation 0x0000000101c8e5bf __CFRunLoopRun + 767
20 CoreFoundation 0x0000000101c8ded3 CFRunLoopRunSpecific + 467
21 GraphicsServices 0x000000010408a3a4 GSEventRunModal + 161
22 UIKit 0x0000000100627a63 UIApplicationMain + 1010
23 Hyderabad Bazar 0x00000001000274e3 main + 115
24 libdyld.dylib 0x00000001028067e1 start + 0
请帮我
最佳答案
您可能会发现更可行的两种不同方法:
子类化UITableViewCell,将UIStepper和UILabel添加为单元格的属性,并将该单元格添加为UISteppers valueChanged操作的目标,并在值更改时更新标签。根据您希望保留事物的方式,这可能会因出队和prepareForReuse而变得不知所措,这将我们带入了另一个想法...
要么
创建一个合适的类变量或属性NSMutableArray,以保存所有单元格的文本,而不管它们是否可见。标签总是从该数组填充,而不是直接从步进器填充。您仍然使用目标/动作对来使单元格响应UIStepper的valueChanged事件,但是您将tableView连接为该单元格的委托,并使用协议从该单元格进行如下调用:
[self.tableViewDelegate newValue:value forCell:self];
然后让tableView实现这样的协议方法:
- (void)newValue:(NSString*)value forCell:(CustomCellClassName*)cell
{
NSIndexPath *indexPath = [self.tableView indexPathForCell:cell];
//now use the index path to set the "value" parameter at the right place in your class variable or property
//Now that the data source is updated, refresh the table
[self.tableView reloadData];
}