有人能帮助我理解如何正确地写下这个案例陈述吗?它不起作用,作为一个傻瓜,我不知道如何解决它:
def hide_link?(link, mailing)
case link
when 'edit' && ['sent', 'sending', 'archived'].include?(mailing.status)
return true
when 'send_schedule' && ['sent', 'sending', 'archived'].include?(mailing.status)
return true
when 'archive' && ['archived'].include?(mailing.status)
puts "I should be in here"
return true
else 'dashboard' && ['sending', 'draft'].include?(mailing.status)
return true
end
end
基本上,当链接符合某些条件时,我希望返回true。
最佳答案
我相信如果link与这些标准不匹配,那么方法应该返回false因此:
def hide_link?(link, mailing)
case link
when 'edit'
['sent', 'sending', 'archived'].include?(mailing.status)
when 'send_schedule'
['sent', 'sending', 'archived'].include?(mailing.status)
when 'archive'
puts "I should be in here"
['archived'].include?(mailing.status)
when 'dashboard'
['sending', 'draft'].include?(mailing.status)
else
false
end
end
构造
[...].include?(mailing.status)
的结果true
或false
将作为hide_link?
方法的结果返回。