python - TypeError:PySide.QtCore.QObject.connect():参数不足

我正在尝试从QThread发出信号以更新progressBar

class Signal(QtCore.QObject):
    this = QtCore.Signal(int)

class Load(QtCore.QThread):
    def __init__(self, parent):
            QtCore.QThread.__init__(self, parent)
            self.parent = parent
            self.onProgress = Signal()

    def run(self):
        '''
        '''
        stacks = []
        count = 100
        for i in range(count):
            # do something ...
            self.onProgress.this.emit(count)

以及我在MainWindow中如何称呼它

    def __init__(self ... ):
            ...
            self.Thread = Load(self)
            self.Thread.onProgress.connect(self.onProgress)
            self.Thread.start()

    @QtCore.Slot(int)
    def onProgress(self, int):
        self.ui.progressBar.setValue(self.ui.progressBar.value() + (90/int))

但我总是得到这个错误

TypeError: PySide.QtCore.QObject.connect(): not enough arguments

最佳答案

您正在连接到onProgress，它是Signal类的实例（在这种情况下，名称具有误导性）。您要连接到onProgress.this，它是实际的信号对象：

self.Thread.onProgress.this.connect(self.onProgress)

或者，将onProgress分配给信号本身：

self.onProgress = Signal().this

关于python - TypeError:PySide.QtCore.QObject.connect():参数不足，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/32237244/