我有一个这样的表“ schLoc”
------------------------
| id | ... | ... | ... |
------------------------
| 1 | ... | ... | ... |
| 2 | ... | ... | ... |
| 3 | ... | ... | ... |
| 4 | ... | ... | ... |
| 5 | ... | ... | ... |
| .. | ... | ... | ... |
------------------------
另一个像这样的“ schLocDett”表,其中schLoc.id = schLocDett.idDoc
-------------------------------
| idDoc | qta | ... | merce |
-------------------------------
| 1 | 1 | ... | fattLoc |
| 1 | 1 | ... | fattSrv |
| 2 | 3 | ... | fattLoc |
| 2 | 2 | ... | notcSrv |
| 2 | 2 | ... | fattSrv |
| 3 | 5 | ... | fattSrv |
| 3 | 3 | ... | notcSrv |
| 3 | 3 | ... | fattLoc |
| 3 | 7 | ... | fattLoc |
| 4 | 5 | ... | notcSrv |
| 4 | 4 | ... | fattSrv |
| 4 | 1 | ... | fattSrv |
| 5 | 1 | ... | notcSrv |
| ... | ... | ... | ....... |
-------------------------------
我想要完整的schLoc列表,并为每个id关联的qta之和,但仅针对merce = fattLoc。如果不存在,则总和为0。
这是我期望的结果
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| id | sumQta | ... | ... |
------------------------
| 1 | 1 | ... | ... |
| 2 | 3 | ... | ... |
| 3 | 10 | ... | ... |
| 4 | 0 | ... | ... |
| 5 | 0 | ... | ... |
| .. | ... | ... | ... |
---------------------------
我尝试这样:
SELECT TOT.sumQta, TAB.*,
FROM schLoc AS TAB, schLocDett AS DETT,
(SELECT idDoc, SUM(qta) AS sumQta
FROM schLocDett
WHERE merce='fattLoc'
GROUP BY idDoc) AS TOT
WHERE TAB.id>0
AND TAB.id=DETT.idDoc
AND TAB.id=TOT.idDoc
但没有获得ID 4和5
任何建议都欢迎
最佳答案
SELECT TAB.*, COALESCE(TOT.sumQta, 0) AS sumQta
FROM schLoc TAB
LEFT JOIN
(
SELECT idDoc, SUM(qta) AS sumQta
FROM schLocDett
WHERE merce = 'fattLoc'
GROUP BY idDoc
) TOT
ON TAB.id = TOT.idDoc
输出:
演示在这里:
Rextester