我目前正在开发使用Google Maps和Ajax的Web应用程序。我都是技术的新手,所以不确定我是否做对了。我按照说明在https://developers.google.com/maps/articles/phpsqlsearch_v3上创建一个。这是我的代码段:

function searchNearLocations(radius){
        var searchUrl = './designIncludes/phpLogicIncludes/searchMarkers.php?lat=' + myLat +'&lng=' + myLng + '&radius=' + radius;
        downloadUrl(searchUrl, function(data) {
            var xml = parseXml(data);
            var markerNodes = xml.documentElement.getElementsByTagName("marker");
            var bounds = new googlemaps.LatLngBounds();
            for (var i = 0; markerNodes.Length; i ++){
                var name = markerNodes[i].getAttribute("name");
                var address = markerNodes[i].getAttribute("address");
                var info = markerNodes[i].getAttribute("info");
                var tts = markerNode[i].getAttribute("tts");
                var slatlng = new google.maps.LatLng(
                    parseFloat(markerNodes[i].getAttribute("lat")),
                    parseFloat(markerNodes[i].getAttribute("lang")));

                createOption(name,distance,i);
                createMarker(latlng,name,address);
                bounds.extend(latlng);
            }
        map.fitBounds(bounds);
        });
    };

function createMarker(slatlng,name,address,info,tts){
    var html = "<b>" + name + "</b></br><u>" + address + "</u></br>" + info + "</br>" + "Time allowance to spend: " + tts;
    var marker = new google.maps.Marker({
        map:map,
        position:slatlng
    });
    google.maps.event.addListener(marker,'click',function(){
        infoWindow.setContent(html);
        infoWindow.open(map,marker);
    });
    markers.push(marker);
};

function downloadUrl(url,callback){
    var request = window.ActiveXObject ?
        new ActiveXObject('Microsoft.XMLHTTP') :
        new XMLHttpRequest;

    request.onreadystatechange = function() {
        if(request.readyState == 4){
            request.onreadystatechange = doNothing;
            callback(request.responseText, request.status);
        }
    };
    request.open('GET',url,true);
    request.send(null);
};

function parseXml(str){
    if (window.ActiveXObject){
        var doc = new ActiveXObject('MicrosoftXMLDOM');
        doc.loadXML(str);
        return doc;
    }else if (window.DOMParse){
        return (new DOMParser).parseFromString(str,'text/xml');
    }
};

function doNothing(){};


我不知道为什么,但是当我使用Mozilla的控制台窗口时,总是得到未定义错误代码xml的信息。当我单击错误时,我指向我

var markerNodes = xml.documentElement.getElementsByTagName("marker");


我什至不知道如何检查我的PHP脚本是否正常工作。我正在使用mysqli而不是上面的Google map tut链接上的mysql。我希望你们能帮助我。如果这是重复的,请给我发送链接。

最佳答案

如果parseXmlwindow.ActiveXObject不存在,您的window.DOMParse函数将返回null

function parseXml(str){
    if (window.ActiveXObject){
        var doc = new ActiveXObject('MicrosoftXMLDOM');
        doc.loadXML(str);
        return doc;
    }else if (window.DOMParse){
        return (new DOMParser).parseFromString(str,'text/xml');
    }
};


您有错别字DOMParse应该是DOMParser(就像在tutorial you reference中一样)

function parseXml(str){
    if (window.ActiveXObject){
        var doc = new ActiveXObject('MicrosoftXMLDOM');
        doc.loadXML(str);
        return doc;
    }else if (window.DOMParser){
        return (new DOMParser).parseFromString(str,'text/xml');
    }
};

09-19 05:50