在我的函数内部遍历for
循环时,即使到达return
语句之后,循环也会无限进行。
此时,j
大于lister.length
。它退出for
循环,并在函数结束时以看似无限的电路跳回到for
循环。
对于我来说,这种行为没有意义,因为return
语句应终止该函数。
这是我的功能:
function permutationLoop(originalArray, listOfPermutations) {
// generates a permutation(Shuffle),and makes sure it is not already in the list of Perms
var lister = generatingPerms(originalArray, listOfPermutations);
//adds the permutation to the list
listOfPermutations.push(lister);
var tester = true;
//This for loop looks through the new permutation to see if it is in-order.
for (var j = 0; j < lister.length; j++) {
//This if statement checks to see as we iterate if it is in order
if (lister[j] > lister[j + 1]) {
tester = false;
}
if (j == (lister.length - 1) && tester == true) {
//Return the permutation number that found the ordered array.
return listOfPermutations.length;
//THIS IS NOT EXITING THE LOOP
}
if (j == lister.length - 1 && tester == false) {
permutationLoop(originalArray, listOfPermutations);
}
}
}
最佳答案
可能您的if语句无效
尝试通过if(true){ ..code.. }
进行测试