我有个问题。即使在不同的def函数中,如何使变量保持在定义中?我有一个函数,它的目的是查看有多少个AIs a user wants,例如,如果他们为他们想要的ais数量选择“一个”。这里定义了ai1:

def AISection():#Same as line 1
    global AI1, AI2, AI3
    print("How many AIs do you want to play with?\nChoices:\n1. One\n2. Two\n3. Three")
    #Asks user next question.
    while(True):
    #Same as line 4.
        UserInput = input("Answer goes here:")
        #same as line 6
        if(UserInput in ['ONE', 'One', 'one']):
        #Same as line 8
            AI1 = 1
            #Only AI1 will be activated.
            break
            #Same as line

所以如果他们只AI1 would be equal 1。一旦发生这种情况,用户将能够选择他们想要多少卡。这是基于他们想要激活多少AIS,所以在前面的段落choose 'One'将被选择,因此他们将有选择从下面的代码中的3个不同的卡数量中选择:
def CardsSection():#Same as line 1
    global AI1, AI2, AI3#Makes sure the AIs are equal to something
    print("How many cards do you want in your hand?")
    #Asks the user for an amount of cards the users wants.
    if(AI1 == 1) and (AI2 == 2):
    #If they choose 2 AIs.
        print("Choices:\n1. Four\n2. Six\n3. Eight")
        #This is so an even amount of cards will be distributed from the deck.
    elif(AI1 == 1) or (AI1 == 1) and (AI3 == 3):
    #If they choose 1 AI or 3 AIs.
        print("Choices:\n1. Five\n2. Seven\n3. Nine")
        #Same is line 68.

但当我运行代码时,它到达AI1 will be equal to 1(aisection后面定义ai1的部分)。然后给了我一个错误:
Traceback (most recent call last):
  File "python", line 81, in <module>
  File "python", line 68, in CardsSection
NameError: name 'AI1' is not defined

问题是我定义了ai1=1,但我的代码无法识别它。我认为这是因为它的定义不同。我想如果我使用全局“模块”,不管我在哪个def函数中,把ai1、ai2和ai3放在一起,它们都是这样的。我怎样才能使它,无论我设置ai1,ai2,和ai3等于(在本例中为aiSection),它们都是那样的,而不管我在哪里?以下是我目前掌握的全部代码:
def StartSection():#The starting section.
    print("Do you want to play?\nChoices:\n1. Yes\n2. No")
    #Asks the user a question.
    while(True):
        #Loops if user doesn't answer properly.
        UserInput = input("Answer goes here:")
        #Prompts the users.
        if(UserInput in ['YES', 'Yes', 'yes']):
        #If user says yes.
            print("Great! Now choose your 'AI Settings'.")
            #Praises the user & tells user about next prompt.
            break
            #Stops the loop. Continues to next prompt.
        elif(UserInput in ['NO', 'No', 'no']):
            #Else, if User says no.
            print("Bye bye!")
            #Farewells to the user.
            quit()
            #Ends Code.
        else:
        #Else user types neither 'Yes' or 'No'.
            print("That is not a choice! Please try again.")
            #Tells user to choose again.
            print("Here are the choices:\n1. Yes\n2. No")
            #Tells user their choices again; goes back to start.
StartSection()#Ends the section of code.
def AISection():#Same as line 1
    global AI1, AI2, AI3
    print("How many AIs do you want to play with?\nChoices:\n1. One\n2. Two\n3. Three")
    #Asks user next question.
    while(True):
    #Same as line 4.
        UserInput = input("Answer goes here:")
        #same as line 6
        if(UserInput in ['ONE', 'One', 'one']):
        #Same as line 8
            AI1 = 1
            #Only AI1 will be activated.
            break
            #Same as line 12
        elif(UserInput in ['TWO', 'Two', 'two']):
        #Same as line 14
            AI1 = 1
            AI2 = 2
            #AI1 and AI2 are activated. AI3 is not activated.
            break
            #Same as line 12
        elif(UserInput in ['THREE', 'Three', 'three']):
        #Same as line 14
            AI1 = 1
            AI2 = 2
            AI3 = 3
            #All 3 AIs are activated.
            break
            #Same as line 12
        else:
            print("That is not a choice! Pleasse try again.")
            #Same as line 22
            print("Here are your choices:\n1. One\n2. Two\n3. Three")
            #Same as line 24
    print("You selested %s AIs" % (UserInput[0].upper()+UserInput[1::1].lower()))
    #Tells the user that what they select while keeping it in a upper-lower case fashion.
AISection()#Same as line 26
def CardsSection():#Same as line 1
    global AI1, AI2, AI3#Makes sure the AIs are equal to something
    print("How many cards do you want in your hand?")
    #Asks the user for an amount of cards the users wants.
    if(AI1 == 1) and (AI2 == 2):
    #If they choose 2 AIs.
        print("Choices:\n1. Four\n2. Six\n3. Eight")
        #This is so an even amount of cards will be distributed from the deck.
    elif(AI1 == 1) or (AI1 == 1) and (AI3 == 3):
    #If they choose 1 AI or 3 AIs.
        print("Choices:\n1. Five\n2. Seven\n3. Nine")
        #Same is line 68.
    else:
        print("Something didn't go right!")
        #If they happened to choose neither 1, 2, or 3 AIs.
        return StartSection()
        #Returns them basck to start.
CardsSection()

我希望这有帮助:)。

最佳答案

我相信您正面临一个scope问题,尽管您将其定义为全局的,但您并没有在函数之外定义它。如果在任何函数之外定义了三个变量,则程序似乎可以工作:

def AISection():
    global AI1, AI2, AI3
    AI1 = 0
    AI2 = 0
    AI3 = 0
    print("How many AIs do you want to play with?\nChoices:\n1. One\n2. Two\n3. Three")
    while True:
        UserInput = input("Answer goes here:")
        if UserInput.lower() == "one":
            AI1 += 1
            break

def CardsSection():
    global AI1, AI2, AI3
    print("How many cards do you want in your hand?")
    if AI1 == 1 and AI2 == 2:
        print("Choices:\n1. Four\n2. Six\n3. Eight")
    elif AI1 == 1 or AI1 == 1 and AI3 == 3:
          print("Choices:\n1. Five\n2. Seven\n3. Nine")

另外请注意,虽然这不是代码检查,但我强烈建议您使用user input.lower()=“one”而不是您的列表检查,它将更有效,并接受更多的答案(例如,如果用户曾经想要输入该答案,则“one”)。

09-19 01:26