我有个问题。即使在不同的def函数中,如何使变量保持在定义中?我有一个函数,它的目的是查看有多少个AIs a user wants
,例如,如果他们为他们想要的ais数量选择“一个”。这里定义了ai1:
def AISection():#Same as line 1
global AI1, AI2, AI3
print("How many AIs do you want to play with?\nChoices:\n1. One\n2. Two\n3. Three")
#Asks user next question.
while(True):
#Same as line 4.
UserInput = input("Answer goes here:")
#same as line 6
if(UserInput in ['ONE', 'One', 'one']):
#Same as line 8
AI1 = 1
#Only AI1 will be activated.
break
#Same as line
所以如果他们只
AI1 would be equal 1
。一旦发生这种情况,用户将能够选择他们想要多少卡。这是基于他们想要激活多少AIS,所以在前面的段落choose 'One'
将被选择,因此他们将有选择从下面的代码中的3个不同的卡数量中选择:def CardsSection():#Same as line 1
global AI1, AI2, AI3#Makes sure the AIs are equal to something
print("How many cards do you want in your hand?")
#Asks the user for an amount of cards the users wants.
if(AI1 == 1) and (AI2 == 2):
#If they choose 2 AIs.
print("Choices:\n1. Four\n2. Six\n3. Eight")
#This is so an even amount of cards will be distributed from the deck.
elif(AI1 == 1) or (AI1 == 1) and (AI3 == 3):
#If they choose 1 AI or 3 AIs.
print("Choices:\n1. Five\n2. Seven\n3. Nine")
#Same is line 68.
但当我运行代码时,它到达
AI1 will be equal to 1
(aisection后面定义ai1的部分)。然后给了我一个错误:Traceback (most recent call last):
File "python", line 81, in <module>
File "python", line 68, in CardsSection
NameError: name 'AI1' is not defined
问题是我定义了ai1=1,但我的代码无法识别它。我认为这是因为它的定义不同。我想如果我使用全局“模块”,不管我在哪个def函数中,把ai1、ai2和ai3放在一起,它们都是这样的。我怎样才能使它,无论我设置ai1,ai2,和ai3等于(在本例中为aiSection),它们都是那样的,而不管我在哪里?以下是我目前掌握的全部代码:
def StartSection():#The starting section.
print("Do you want to play?\nChoices:\n1. Yes\n2. No")
#Asks the user a question.
while(True):
#Loops if user doesn't answer properly.
UserInput = input("Answer goes here:")
#Prompts the users.
if(UserInput in ['YES', 'Yes', 'yes']):
#If user says yes.
print("Great! Now choose your 'AI Settings'.")
#Praises the user & tells user about next prompt.
break
#Stops the loop. Continues to next prompt.
elif(UserInput in ['NO', 'No', 'no']):
#Else, if User says no.
print("Bye bye!")
#Farewells to the user.
quit()
#Ends Code.
else:
#Else user types neither 'Yes' or 'No'.
print("That is not a choice! Please try again.")
#Tells user to choose again.
print("Here are the choices:\n1. Yes\n2. No")
#Tells user their choices again; goes back to start.
StartSection()#Ends the section of code.
def AISection():#Same as line 1
global AI1, AI2, AI3
print("How many AIs do you want to play with?\nChoices:\n1. One\n2. Two\n3. Three")
#Asks user next question.
while(True):
#Same as line 4.
UserInput = input("Answer goes here:")
#same as line 6
if(UserInput in ['ONE', 'One', 'one']):
#Same as line 8
AI1 = 1
#Only AI1 will be activated.
break
#Same as line 12
elif(UserInput in ['TWO', 'Two', 'two']):
#Same as line 14
AI1 = 1
AI2 = 2
#AI1 and AI2 are activated. AI3 is not activated.
break
#Same as line 12
elif(UserInput in ['THREE', 'Three', 'three']):
#Same as line 14
AI1 = 1
AI2 = 2
AI3 = 3
#All 3 AIs are activated.
break
#Same as line 12
else:
print("That is not a choice! Pleasse try again.")
#Same as line 22
print("Here are your choices:\n1. One\n2. Two\n3. Three")
#Same as line 24
print("You selested %s AIs" % (UserInput[0].upper()+UserInput[1::1].lower()))
#Tells the user that what they select while keeping it in a upper-lower case fashion.
AISection()#Same as line 26
def CardsSection():#Same as line 1
global AI1, AI2, AI3#Makes sure the AIs are equal to something
print("How many cards do you want in your hand?")
#Asks the user for an amount of cards the users wants.
if(AI1 == 1) and (AI2 == 2):
#If they choose 2 AIs.
print("Choices:\n1. Four\n2. Six\n3. Eight")
#This is so an even amount of cards will be distributed from the deck.
elif(AI1 == 1) or (AI1 == 1) and (AI3 == 3):
#If they choose 1 AI or 3 AIs.
print("Choices:\n1. Five\n2. Seven\n3. Nine")
#Same is line 68.
else:
print("Something didn't go right!")
#If they happened to choose neither 1, 2, or 3 AIs.
return StartSection()
#Returns them basck to start.
CardsSection()
我希望这有帮助:)。
最佳答案
我相信您正面临一个scope问题,尽管您将其定义为全局的,但您并没有在函数之外定义它。如果在任何函数之外定义了三个变量,则程序似乎可以工作:
def AISection():
global AI1, AI2, AI3
AI1 = 0
AI2 = 0
AI3 = 0
print("How many AIs do you want to play with?\nChoices:\n1. One\n2. Two\n3. Three")
while True:
UserInput = input("Answer goes here:")
if UserInput.lower() == "one":
AI1 += 1
break
def CardsSection():
global AI1, AI2, AI3
print("How many cards do you want in your hand?")
if AI1 == 1 and AI2 == 2:
print("Choices:\n1. Four\n2. Six\n3. Eight")
elif AI1 == 1 or AI1 == 1 and AI3 == 3:
print("Choices:\n1. Five\n2. Seven\n3. Nine")
另外请注意,虽然这不是代码检查,但我强烈建议您使用user input.lower()=“one”而不是您的列表检查,它将更有效,并接受更多的答案(例如,如果用户曾经想要输入该答案,则“one”)。