c++ - 简单的libcurl应用-segfault

我无法确定我的代码存在段错误？

基本上，它通过SSL(HTTPS)安全连接连接到服务器，并进行GET，以提供MachineID(程序将其作为参数)。

还应该设置一些自定义标题。然后，我将返回的正文和标题保存为单独的文本文件。 (基本上它将运行一个shell脚本，因此我的远程系统可以自动从我的服务器中获取“订单”)

但是它存在segfaults，我唯一要在其上进行开发的linux机器是我的VPS，由于其奇怪的虚拟化，它总是在加载GDB时崩溃...:o

谁能告诉我问题出在哪里？ -我认为它几乎可以肯定在我的字符串连接中-在其中建立标题，并请求URL。

编辑:啊，忘记了密码!



#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <curl/curl.h>
#include <string.h>

 static size_t write_data(void *ptr, size_t size, size_t nmemb, void *stream)
{
 int written = fwrite(ptr, size, nmemb, (FILE *)stream);
 return written;
}

int main(int argc, char *argv[])
{
static const char *headerfilename = "head.out";
static const char *bodyfilename = "body.out";

char *url = "https://fakeserver.fakesite.com:8443/SystemManager/getOrders.jsp?machineID=";
char *customHeader = "MachineID:";
char *machineID = NULL;

struct curl_slist *chunk = NULL;

CURL *curl;
CURLcode res;
FILE *headerfile;
FILE *bodyfile;

    if (argc == 2)
{
    machineID = argv[1];
    strcat(url,machineID);
}
else
{
 printf("Usage: %s <MachineID>\n", argv[0]);
 return 1;
}

 curl_global_init(CURL_GLOBAL_SSL);

 // init the curl session
 curl = curl_easy_init();

 if(curl) {
    // set URL to get

 curl_easy_setopt(curl, CURLOPT_URL, url);

    // no progress meter please
    curl_easy_setopt(curl, CURLOPT_NOPROGRESS, 1L);

    // send all data to this function
 curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_data);

 // some servers don't like requests that are made without a user-agent field, so we provide one
 curl_easy_setopt(curl, CURLOPT_USERAGENT, "libcurl-agent/1.0");

 // Also add a custom MachineID header
 strcat(customHeader, machineID);
 chunk = curl_slist_append(chunk, customHeader);
 res = curl_easy_setopt(curl, CURLOPT_HTTPHEADER, chunk);

    // These tweaks must be enabled for my dodgy self-signed certificate.

    // DONT bother verifying our certificate is signed by a trusted CA.
    curl_easy_setopt(curl, CURLOPT_SSL_VERIFYPEER, 0L);
    // DONT check the hostname on the certificate matcheds the remote system.
    curl_easy_setopt(curl, CURLOPT_SSL_VERIFYHOST, 0L);


    // open the files
 headerfile = fopen(headerfilename,"w");
 if (headerfile == NULL) {
 curl_easy_cleanup(curl);
 return -1;
 }
 else
 {
 // we want the headers to this file handle
 curl_easy_setopt(curl, CURLOPT_WRITEHEADER, headerfile);
 }

 bodyfile = fopen(bodyfilename,"w");
 if (bodyfile == NULL) {
 curl_easy_cleanup(curl);
 return -1;
 }
 else
 {
 // we want the body to this file handle
 curl_easy_setopt(curl, CURLOPT_WRITEDATA, bodyfile);
 }
     // get it!
 res = curl_easy_perform(curl);

    // close the files
 fclose(headerfile);
 fclose(bodyfile);

 // always cleanup curl stuff
 curl_easy_cleanup(curl);
 }
 curl_global_cleanup();
 return 0;
}
                                    最佳答案            
            
            您正在使用字符串文字作为strcat的目标。您需要为指针分配内存，然后在strcpy和strcat函数中将它们用作目标

字符串文字通常位于RO区域中，写入此类区域可能会调用未定义行为

改变像
char *url

至
char url[100];

还可以考虑使用n，strcat和适当的缓冲区大小的strcpy版本，以防止意外的缓冲区溢出
关于c++ - 简单的libcurl应用-segfault，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/10362487/

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c++ - 简单的libcurl应用-segfault