有人可以帮我这个代码吗?我需要从routeToRoom函数返回一个值:

var sys = require('sys');

function routeToRoom(userId, passw) {
    var roomId = 0;
    var nStore = require('nstore/lib/nstore').extend(require('nstore/lib/nstore/query')());
    var users = nStore.new('data/users.db', function() {

        users.find({
            user: userId,
            pass: passw
        }, (function(err, results) {
            if (err) {
                roomId = -1;
            } else {
                roomId = results.creationix.room;
            }
        }
        ));
    });
    return roomId;
}
sys.puts(routeToRoom("alex", "123"));

但我总是得到:0

我猜return roomId;roomId=results.creationix.room之前执行。有人可以帮我这个代码吗?

最佳答案

function routeToRoom(userId, passw, cb) {
    var roomId = 0;
    var nStore = require('nstore/lib/nstore').extend(require('nstore/lib/nstore/query')());
    var users = nStore.new('data/users.db', function() {
        users.find({
            user: userId,
            pass: passw
        }, function(err, results) {
            if (err) {
                roomId = -1;
            } else {
                roomId = results.creationix.room;
            }
            cb(roomId);
        });
    });
}
routeToRoom("alex", "123", function(id) {
    console.log(id);
});

您需要使用回调。这就是异步IO的工作方式。 Btw sys.puts已弃用

关于javascript - 从函数返回结果(javascript,nodejs),我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/7255956/

10-10 00:33