我正在寻找一种解决方案,它允许我编写本地EmacsLisp代码,并在编译时将其转换为HTML,如Franz's htmlgen:
(html
((:div class "post")
(:h1 "Title")
(:p "Hello, World!")))
当然,我可以,但如果有任何项目围绕这个问题,我很感兴趣。
最佳答案
当您从列表结构中生成XML时。我发现它支持的“xmlgen”包与emacs的格式不完全相反,这让我很失望。
我确实在我的xmlgen副本中添加了这个:
;; this creates a routine to be the inverse of what xml-parse does
;;;###autoload
(defun xml-gen (form &optional in-elm level)
"Convert a sexp to xml:
'(p :class \"big\")) => \"<p class=\\\"big\\\" />\""
(let ((level (or level 0)))
(cond
((numberp form) (number-to-string form))
((stringp form) form)
((listp form)
(destructuring-bind (xml attrs) (xml-gen-extract-plist form)
(let ((el (car xml)))
(unless (symbolp el)
(error "Element must be a symbol (got '%S')." el))
(setq el (symbol-name el))
(concat "<" el (xml-gen-attr-to-string attrs)
(if (> (length xml) 1)
(concat ">" (mapconcat
(lambda (s) (xml-gen s el (1+ level)))
(cdr xml)
"")
"</" el ">")
"/>"))))))))
(defun xml-gen-attr-to-string (plist)
(reduce 'concat (mapcar (lambda (p) (concat " " (symbol-name (car p)) "=\"" (cdr p) "\"")) plist)))
(defun xml-gen-extract-plist (list)
(list (cons (car list) (let ((kids (xml-node-children list)))
(if (= 1 (length kids))
kids
(remove-if-not 'listp kids))))
(xml-node-attributes list)))
注意:这个接口是
xmlgen
(而不是原来的解析)。通过此接口,以下内容适用:
(string-equal (xml-gen (car (xml-parse-region <some-region-of-xml>)))
<some-region-of-xml>)
和
(equal (car (xml-parse-region (insert (xml-gen <some-xml-form>))))
<some-xml-form>)
新的
xml-gen
并不努力保留xmlgen
例程生成的空白。