我正在寻找一种解决方案,它允许我编写本地EmacsLisp代码,并在编译时将其转换为HTML,如Franz's htmlgen

(html
 ((:div class "post")
  (:h1 "Title")
  (:p "Hello, World!")))

当然,我可以,但如果有任何项目围绕这个问题,我很感兴趣。

最佳答案

当您从列表结构中生成XML时。我发现它支持的“xmlgen”包与emacs的格式不完全相反,这让我很失望。
我确实在我的xmlgen副本中添加了这个:

;; this creates a routine to be the inverse of what xml-parse does
;;;###autoload
(defun xml-gen (form &optional in-elm level)
  "Convert a sexp to xml:
  '(p :class \"big\")) => \"<p class=\\\"big\\\" />\""
  (let ((level (or level 0)))
    (cond
     ((numberp form) (number-to-string form))
     ((stringp form) form)
     ((listp form)
      (destructuring-bind (xml attrs) (xml-gen-extract-plist form)
        (let ((el (car xml)))
          (unless (symbolp el)
            (error "Element must be a symbol (got '%S')." el))
          (setq el (symbol-name el))
          (concat "<" el (xml-gen-attr-to-string attrs)
                  (if (> (length xml) 1)
                      (concat ">" (mapconcat
                                   (lambda (s) (xml-gen s el (1+ level)))
                                   (cdr xml)
                                   "")
                              "</" el ">")
                    "/>"))))))))

(defun xml-gen-attr-to-string (plist)
  (reduce 'concat (mapcar (lambda (p) (concat " " (symbol-name (car p)) "=\"" (cdr p) "\"")) plist)))

(defun xml-gen-extract-plist (list)
  (list (cons (car list) (let ((kids (xml-node-children list)))
                           (if (= 1 (length kids))
                               kids
                             (remove-if-not 'listp kids))))
        (xml-node-attributes list)))

注意:这个接口是xmlgen(而不是原来的解析)。
通过此接口,以下内容适用:
(string-equal (xml-gen (car (xml-parse-region <some-region-of-xml>)))
              <some-region-of-xml>)


(equal (car (xml-parse-region (insert (xml-gen <some-xml-form>))))
       <some-xml-form>)

新的xml-gen并不努力保留xmlgen例程生成的空白。

09-17 18:34