当使用q时,我得到相同的响应,它循环的次数:
function start() {
var the_promises = [];
var api_info = config.AFV
var deferred = Q.defer();
var extPath = '/search/'
var callType = 'GET'
var mymd = buildmd5(api_info, extPath, callType);
for(var page=1;page<4;page++) {
console.log('getting page:'+page)
new Client().get(url'+page, function(data, response){
deferred.resolve(data);
});
the_promises.push(deferred.promise);
}
return Q.all(the_promises);
}
start().then(function (clips) {
inspect(clips)
});
输出:
resultPageNumber:['1'],
resultPageNumber:['1'],
resultPageNumber:['1'],
resultPageNumber:['1'],
我觉得我可能有var deferred = Q.defer();在错误的地方,它就不能兑现不同的承诺。我知道此版本的代码不起作用,但我只关心诺言。谢谢!
最佳答案
您需要为每个新客户端创建一个新的延迟。并在立即调用的函数中抛出该循环体以适当地确定var的范围。
function start() {
var the_promises = [];
var api_info = config.AFV;
var extPath = '/search/';
var callType = 'GET';
var mymd = buildmd5(api_info, extPath, callType);
for(var page=1;page<4;page++) {
(function() {
var deferred = Q.defer();
console.log('getting page:'+page);
new Client().get('url'+page, function(data, response){
deferred.resolve(data);
});
the_promises.push(deferred.promise);
}());
}
return Q.all(the_promises);
}
start().then(function (clips) {
inspect(clips);
});