javascript - 星级评分系统:CSS仅在一个实例上有效

我有星级评分系统。

HTML部分是通过php在foreach中添加的，并包含在图像库中以添加评分系统。我以该代码为例，在通过jQuery使用DB_result进行检查的真实代码中运行正常，但20张图像中只有一张显示了星号

我该如何解决？通过分页总共添加了5000张图像

PhP部分是这样的：

foreach ($xxx AS $X){
//cake php simply echo the file where the inputfields are in
echo $this->Element('../Candidates/Elements/rating_display')

}

// for the number 2 comes the php variable
$(".vote[value='2']").attr("checked", true);

.rating {
    float:left;
}

/* :not(:checked) is a filter, so that browsers that don’t support :checked don’t
   follow these rules. Every browser that supports :checked also supports :not(), so
   it doesn’t make the test unnecessarily selective */
.rating:not(:checked) > input {
    position:absolute;
    top:-9999px;
    clip:rect(0,0,0,0);
}

.rating:not(:checked) > label {
    float:right;
    width:1em;
    padding:0 .1em;
    overflow:hidden;
    white-space:nowrap;
    cursor:pointer;
    font-size:200%;
    line-height:1.2;
    color:#ddd;
    text-shadow:1px 1px #bbb, 2px 2px #666, .1em .1em .2em rgba(0,0,0,.5);
}

.rating:not(:checked) > label:before {
    content: '★ ';
}

.rating > input:checked ~ label {
    color: #f70;
    text-shadow:1px 1px #c60, 2px 2px #940, .1em .1em .2em rgba(0,0,0,.5);
}

.rating:not(:checked) > label:hover,
.rating:not(:checked) > label:hover ~ label {
    color: gold;
    text-shadow:1px 1px goldenrod, 2px 2px #B57340, .1em .1em .2em rgba(0,0,0,.5);
}

.rating > input:checked + label:hover,
.rating > input:checked + label:hover ~ label,
.rating > input:checked ~ label:hover,
.rating > input:checked ~ label:hover ~ label,
.rating > label:hover ~ input:checked ~ label {
    color: #ea0;
    text-shadow:1px 1px goldenrod, 2px 2px #B57340, .1em .1em .2em rgba(0,0,0,.5);
}

.rating > label:active {
    position:relative;
    top:2px;
    left:2px;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<fieldset class="rating">
    <legend>Please rate:</legend>
    <input type="radio" id="star5" name="rating" value="5" class="vote"/><label for="star5" title="Rocks!">5 stars</label>
    <input type="radio" id="star4" name="rating" value="4" class="vote" /><label for="star4" title="Pretty good">4 stars</label>
    <input type="radio" id="star3" name="rating" value="3" class="vote"/><label for="star3" title="Meh">3 stars</label>
    <input type="radio" id="star2" name="rating" value="2" class="vote"/><label for="star2" title="Kinda bad">2 stars</label>
    <input type="radio" id="star1" name="rating" value="1" class="vote"/><label for="star1" title="Sucks big time">1 star</label>
</fieldset>
<fieldset class="rating">
    <legend>Please rate:</legend>
    <input type="radio" id="star5" name="rating" value="5" class="vote"/><label for="star5" title="Rocks!">5 stars</label>
    <input type="radio" id="star4" name="rating" value="4" class="vote" /><label for="star4" title="Pretty good">4 stars</label>
    <input type="radio" id="star3" name="rating" value="3" class="vote"/><label for="star3" title="Meh">3 stars</label>
    <input type="radio" id="star2" name="rating" value="2" class="vote"/><label for="star2" title="Kinda bad">2 stars</label>
    <input type="radio" id="star1" name="rating" value="1" class="vote"/><label for="star1" title="Sucks big time">1 star</label>
</fieldset>

最佳答案

由于输入中的ID重复，因此它仅适用于一个实例。使它们与众不同-总是:)