下面的代码返回两个简明的JSON字符串和错误的content-type text/plain
。应该是application/vnd.api+json
package main
import (
"github.com/google/jsonapi"
"github.com/labstack/echo"
"net/http"
)
type Album struct {
ID int `jsonapi:"primary,albums"`
Name string `jsonapi:"attr,name"`
}
func main() {
e := echo.New()
e.GET("/", func(c echo.Context) error {
jsonapi.MarshalManyPayload(c.Response(), albumList())
return c.JSON(http.StatusOK, c.Response())
})
e.Logger.Fatal(e.Start(":1323"))
}
func albumList() []*Album {
a1 := Album{123, "allbum1"}
a2 := Album{456, "allbum2"}
albums := []*Album{&a1, &a2}
return albums
}
错误的输出(两个简明的json)。第一个是正确的
jsonapi
结构,我认为第二个与echo-framework
相关:{
"data": [
{
"type": "albums",
"id": "123",
"attributes": {
"name": "allbum1"
}
},
{
"type": "albums",
"id": "456",
"attributes": {
"name": "allbum2"
}
}
]
}
{
"Writer": {},
"Status": 200,
"Size": 133,
"Committed": true
}
这段代码解决了这个问题,但是看起来很尴尬。我觉得有一种更好的方法可以使用
echo
来简化它。e.GET("/", func(c echo.Context) error {
var b bytes.Buffer
body := bufio.NewWriter(&b)
err := jsonapi.MarshalManyPayload(body, albumList())
if err != nil {
fmt.Println(err)
}
body.Flush()
return c.JSONBlob(http.StatusOK, b.Bytes())
})
任何的想法?
最佳答案
您的代码看起来还不错。但是,它可以简化-
var b bytes.Buffer // you could use buffer pool here
err := jsonapi.MarshalManyPayload(&b, albumList())
if err != nil {
return err
}
return c.JSONBlob(http.StatusOK, b.Bytes())
以下是您的想法的方法:
方法1-
c.Response().Header().Set(echo.HeaderContentType, jsonapi.MediaType)
c.Response().WriteHeader(http.StatusOK)
return jsonapi.MarshalManyPayload(c.Response(), albumList())
方法2-
var b bytes.Buffer // you could use buffer pool here
err := jsonapi.MarshalManyPayload(&b, albumList())
if err != nil {
return err
}
c.Response().Header().Set(echo.HeaderContentType, jsonapi.MediaType)
c.Response().WriteHeader(http.StatusOK)
_, err := b.WriteTo(c.Response())
return err
关于go - 如何使用Google/jsonapi和echo框架返回有效的jsonapi响应,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/44515677/