我正在使用Windows应用程序,在该对话框中,我在对话框中查询Postgres的一些数据,并在表小部件中手动显示输出。
m_ui->tableWidget->setRowCount(joinedData.count());
for(int i=0; i<joinedData.count(); i++) //for each row
{
m_ui->tableWidget->setItem(i, 0, new QTableWidgetItem(joinedData[i].bobin.referenceNumber));
m_ui->tableWidget->setItem(i, 1, new QTableWidgetItem(QString::number(joinedData[i].bobin.width)));
m_ui->tableWidget->setItem(i, 2, new QTableWidgetItem(QString::number(joinedData[i].tolerance.getHole())));
m_ui->tableWidget->setItem(i, 3, new QTableWidgetItem(QString::number(joinedData[i].tolerance.getLessThanZeroFive()))); m_ui->tableWidget->setItem(i, 4, new QTableWidgetItem(QString::number(joinedData[i].tolerance.getZeroFive_to_zeroSeven())));
m_ui->tableWidget->setItem(i, 5, new QTableWidgetItem(QString::number(joinedData[i].tolerance.getZeroFive_to_zeroSeven_repetitive())));
m_ui->tableWidget->setItem(i, 6, new QTableWidgetItem(QString::number(joinedData[i].tolerance.getZeroSeven_to_Three())));
m_ui->tableWidget->setItem(i, 7, new QTableWidgetItem(QString::number(joinedData[i].tolerance.getThree_to_five())));
m_ui->tableWidget->setItem(i, 8, new QTableWidgetItem(QString::number(joinedData[i].tolerance.getMoreThanFive())));
}
另外,基于行和列的信息,我将其中一些tablewidgetitems绘制为某些颜色,但我认为这并不重要。
我重新实现了QDialog的contextMenuEvent,以获得右键单击的tableWidgetItem的行和列坐标:
void BobinFlanView::contextMenuEvent(QContextMenuEvent *event)
{
QMenu menu(m_ui->tableWidget);
//standard actions
menu.addAction(this->markInactiveAction);
menu.addAction(this->markActiveAction);
menu.addSeparator();
menu.addAction(this->exportAction);
menu.addAction(this->exportAllAction);
//obtain the rightClickedItem
QTableWidgetItem* clickedItem = m_ui->tableWidget->itemAt(m_ui->tableWidget->mapFromGlobal(event->globalPos()));
// if it's a colored one, add some more actions
if (clickedItem && clickedItem->column()>1 && clickedItem->row()>0)
{
//this is a property, i'm keeping this for a later use
this->lastRightClickedItem = clickedItem;
//debug purpose:
QMessageBox::information(this, "", QString("clickedItem = %1, %2").arg(clickedItem->row()).arg(clickedItem->column()));
QMessageBox::information(this, "", QString("globalClick = %1, %2\ntransformedPos = %3, %4").arg(event->globalX()).arg(event->globalY())
.arg(m_ui->tableWidget->mapFromGlobal(event->globalPos()).x()).arg(m_ui->tableWidget->mapFromGlobal(event->globalPos()).y()));
menu.addSeparator();
menu.addAction(this->changeSelectedToleranceToUygun);
menu.addAction(this->changeSelectedToleranceToUyar);
menu.addAction(this->changeSelectedToleranceToDurdurUyar);
//... some other irrevelant 'enable/disable' activities
menu.exec(event->globalPos());
}
问题是,当我右键单击同一项目时,我会获得相同的全局坐标,但会随机获得不同的行列信息。例如,全局pos正好是600,230,但行列对是随机(5,3)和(4,3)。我的意思是什么?!
另外,当我从最后一行到行(大于13)单击某个项目时,它永远不会进入条件“如果(clickedItem && clickedItem-> column()> 1 && clickedItem-> row()> 0)” ,我认为主要是因为'clickedItem'为null。
为了获得帮助,我将非常高兴分享任何更多信息,甚至是完整的cpp-h-ui三重奏。
非常感谢。
最佳答案
试试这个:
QTableWidgetItem* clickedItem = m_ui->tableWidget->itemAt(event->pos());
问题是您试图将全局位置映射到表窗口小部件位置,而不考虑可滚动区域。要将全局位置映射到可以传递给
itemAt
的内容中,请使用tableWidget->viewport()->mapFromGlobal
。