如标题所述,我想以编程方式检查域的DNS响应是否受DNSSEC保护。
我该怎么办?
如果有针对此的pythonic解决方案,那就太好了。
更新:
更改了回复请求,对于造成的困惑,我们深表歉意
最佳答案
使用DNS解析器(例如dnspython
),您可以查询域的DNSKEY RRset并打开DO
(dnssec OK)查询标志。如果查询成功,则答案将设置AD
(已认证数据)标志,并将包含区域的RRSIG签名(如果已签名)。
更新:使用dnspython
的基本示例
import dns.name
import dns.query
import dns.dnssec
import dns.message
import dns.resolver
import dns.rdatatype
# get nameservers for target domain
response = dns.resolver.query('example.com.',dns.rdatatype.NS)
# we'll use the first nameserver in this example
nsname = response.rrset[0].to_text() # name
response = dns.resolver.query(nsname,dns.rdatatype.A)
nsaddr = response.rrset[0].to_text() # IPv4
# get DNSKEY for zone
request = dns.message.make_query('example.com.',
dns.rdatatype.DNSKEY,
want_dnssec=True)
# send the query
response = dns.query.udp(request,nsaddr)
if response.rcode() != 0:
# HANDLE QUERY FAILED (SERVER ERROR OR NO DNSKEY RECORD)
# answer should contain two RRSET: DNSKEY and RRSIG(DNSKEY)
answer = response.answer
if len(answer) != 2:
# SOMETHING WENT WRONG
# the DNSKEY should be self signed, validate it
name = dns.name.from_text('example.com.')
try:
dns.dnssec.validate(answer[0],answer[1],{name:answer[0]})
except dns.dnssec.ValidationFailure:
# BE SUSPICIOUS
else:
# WE'RE GOOD, THERE'S A VALID DNSSEC SELF-SIGNED KEY FOR example.com
关于python - 以编程方式检查域是否受 DNSSEC 保护,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/26137036/