我一直在使用Xsrteam将XML解析为ArrayList。它起作用了,但是由于某种原因我无法到达数组的内容。

处理ArrayList数据的类:

@XStreamAlias("BOARDS")
public class Boards {
    @XStreamImplicit(itemFieldName = "id")
    public ArrayList ids = new ArrayList();

    //region GETTERS-SETTERS
    public void setIds(ArrayList temp){
        this.ids = temp;
    }
    public List getIds(){
        return ids;
    }
//    endregion
}

@XStreamAlias("id")
class Id {

    @XStreamAlias("board")
    private String board;

    @XStreamAlias("description")
    private String description;

    @XStreamAlias("price")
    private String price;

    @XStreamAlias("shape")
    private String shape;

    @XStreamAlias("riding_level")
    private String ridingLevel;

    @XStreamAlias("riding_style")
    private String ridingStyle;

    @XStreamAlias("camber_profile")
    private String camber;

    @XStreamAlias("stance")
    private String stance;

    @XStreamAlias("picture")
    private String picture;

    <<public getters - setters here>>
}


我如何尝试访问这些getters

Boards boards = (Boards) xstream.fromXML(reader); // parse xml into array list
boards.getIds().get(0).getPrice(); //!!getPrice() cannot be resolved


firstObject first = boards.getIds().get(0);

这是使用调试器的外观:

最佳答案

Boards具有原始类型,因为不清楚,ArrayList ids中应包含哪些对象类型。因此,您应该显式地转换boards.getIds().get(0)的结果:

((Id) boards.getIds().get(0)).getPrice()


或生成Boards类:

public class Boards<E> {

    public List<E> ids = new ArrayList<E>();

    //region GETTERS-SETTERS
    public void setIds(ArrayList<E> temp){
        this.ids = temp;
    }
    public List<E> getIds(){
        return ids;
    }
//    endregion
}


您可以阅读有关泛型here的信息

10-06 12:41