java - 如何在Java中解析String XML

我有一个String XML。我需要从Java中的XML获取项目ISSUCCESS值。但是项目值返回null。这是我的XML代码。


XML格式

<QRYRESULT><ISSUCCESS>N</ISSUCCESS><REASON>E002</REASON><WARNING>1. Transaction date Should be current date.11-SEP-18  E </WARNING></QRYRESULT>

我已经写了下面的代码来获取ISSUCCESS项目的值。

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(**myXML**));
Document doc = db.parse(is);
NodeList nodeList = doc.getElementsByTagName("QRYRESULT");
for (int i = 0; i < nodeList.getLength(); i++) {
    Element value = (Element) nodeList.item(i);
    String ISSUCCESS = value.getAttribute("ISSUCCESS");
    System.out.println("ISSUCCESS = " + ISSUCCESS);
}

最佳答案

ISSUCCESS是元素而不是属性。

改成：

NodeList nodeList = doc.getElementsByTagName("QRYRESULT");
for (int i = 0; i < nodeList.getLength(); i++) {
    Element value = (Element) nodeList.item(i);

    String ISSUCCESS = value.getElementsByTagName("ISSUCCESS").item(0).getTextContent();
    System.out.println("ISSUCCESS = " + ISSUCCESS);
}