我有以下程序
List<String> numbers = Arrays.asList("10", "68", "97", "9", "21", "12");
Collections.sort(numbers, (a, b) -> (b + a).compareTo(a + b));
你好
我该如何重写此代码
(b + a).compareTo(a + b)
到Comparator.comparing
先感谢您。
最佳答案
Comparator.comparing()结构旨在用于具有多个字段的对象,因此您可以提取所需的字段用作键。
此方法接受用于提取可比较排序键的函数作为参数。
但是,对于对List 进行排序,则不需要这样做。
由于只有您的String值,没有其他可用作键的不明确字段。
如果要对此列表排序(a + b).compareTo(b + a)
List<String> numbers = Arrays.asList("10", "68", "97", "9", "21", "12");
然后用标准比较器编写代码:
numbers.sort((a, b) -> (a+b).compareTo(b+a));
以及使用Compartor.comparing的代码:
numbers.sort(Comparator.comparing((String s) -> s, (a, b) -> (a+b).compareTo(b+a)));
都将输出:
[ 10, 12, 21, 68, 97, 9 ]
但是如您所见,在List 上这是不必要的,并且最终会重复代码。
如果不清楚,那么这里是Comparator.comparing正确使用案例的示例
假设我们有这堂课
public class Car {
private String name;
private String type;
private int tires;
public Car(String name, String type, int tires) {
this.name = name;
this.type = type;
this.tires= tires;
}
public String getName() {
return name;
}
public String getType() {
return type;
}
public int getTires() {
return tires;
}
}
和汽车清单
List<Car> carsList = new ArrayList<Car>();
carsList.add(new Car("Audi A3", "Hatchback", 4));
carsList.add(new Car("Tyrerell P34", "Formula One", 6));
carsList.add(new Car("1932 Morgan Aero 2-Seater Sports", "Sports", 3));
carsList.add(new Car("Avtoros Shaman", "All terrain", 8));
然后我们可以像这样对List 进行排序
// By the type
carsList.sort(Comparator.comparing(Car::getType));
// By the number of tires
carsList.sort(Comparator.comparingInt(Car::getTires));
// By the number of tires in reverse order
carsList.sort(Comparator.comparingInt(Car::getTires).reversed());
// First by the type and then by the number of tires in reverse order
carsList.sort(Comparator.comparing(Car::getType).thenComparing(Car::getTires).reversed());