我试图在最后用do while循环编写此复利程序,但我不知道如何打印最终金额。
这是我到目前为止的代码:
public static void main(String[] args) {
double amount;
double rate;
double year;
System.out.println("This program, with user input, computes interest.\n" +
"It allows for multiple computations.\n" +
"User will input initial cost, interest rate and number of years.");
Scanner keyboard = new Scanner(System.in);
System.out.println("What is the initial cost?");
amount = keyboard.nextDouble();
System.out.println("What is the interest rate?");
rate = keyboard.nextDouble();
rate = rate/100;
System.out.println("How many years?");
year = keyboard.nextInt();
for (int x = 1; x < year; x++){
amount = amount * Math.pow(1.0 + rate, year);
}
System.out.println("For " + year + " years an initial " + amount + " cost compounded at a rate of " + rate + " will grow to " + amount);
String go = "n";
do{
System.out.println("Continue Y/N");
go = keyboard.nextLine();
}while (go.equals("Y") || go.equals("y"));
}
}
最佳答案
问题是amount = amount * Math.pow(1.0 + rate, year);
。您正在用计算出的金额覆盖原始金额。您需要一个单独的值来保存计算所得的值,同时仍保留原始值。
所以:
double finalAmount = amount * Math.pow(1.0 + rate, year);
然后在您的输出中:
System.out.println("For " + year + " years an initial " + amount +
" cost compounded at a rate of " + rate + " will grow to " + finalAmount);
编辑:或者,您可以保存一行,一个变量,然后直接进行内联计算,如下所示:
System.out.println("For " + year + " years an initial " + amount +
" cost compounded at a rate of " + rate + " will grow to " +
(amount * Math.pow(1.0 + rate, year)));