我正在编写一个程序,要求用户输入两个整数,总共十次。

接下来,程序需要评估第一个整数是否为第二个整数的倍数。

如果第一个是第二个的倍数,则程序应打印出“ true”,如果不是,则应打印出“ false”。

这是我的代码:

     public static void main(String[] args) {

         Scanner input = new Scanner(System.in);

         int counter = 0; // Initializes the counter

         System.out.printf("Enter first integer: "); // asks the user for the first integer
         int number1 = input.nextInt(); // stores users input for the first integer

         System.out.printf("Enter second integer: "); // asks the user for the second integer
         int number2 = input.nextInt(); // stores the users input for the second integer

         while (counter <= 10) // starts a loop that goes to 10
         {
             if (number1 & number2 == 0) // checks to see if number1 is a multiple of number2
                 System.out.print("true"); // if so then print out "true"
             else
                 System.out.print("false"); // otherwise print out "false"
         }

     } // end class


沿线的某个地方我的代码坏了。有没有人可以帮助您,或者至少可以向我指出正确的方向?

最佳答案

您需要读取两次输入10次。并测试number1是否为number2的倍数。就像是

public static void main(String str[]) throws IOException {
    Scanner input = new Scanner(System.in);

    for (int counter = 0; counter < 10; counter++) {
        System.out.printf("Enter first integer for counter %d: ", counter);
        int number1 = input.nextInt();

        System.out.printf("Enter second integer for counter %d: ", counter);
        int number2 = input.nextInt();

        // Since you want to print true if number1 is a multiple of number2.
        System.out.println(number1 % number2 == 0);
    }
}

10-08 00:39