我的表结构是

CREATE TABLE IF NOT EXISTS `tbl_user_result` (
   `Id` int(11) NOT NULL AUTO_INCREMENT,
   `ResultId`int(11),
   `PaperId` int(11) ,
   `Title` varchar(45),
   `TotalQuestions` int(11) ,
   `Attempt` int(11) ,
   `Correct` int(11) ,
   `Wrong` int(11) ,
   `Score` int(45) ,
   `Minutes` int(11) ,
   `TimeSt` varchar(45) ,
   `UserEmail` varchar(45) ,
   `UserName` varchar(45) ,
  PRIMARY KEY (`Id`));


我尝试了以下SQL查询

SELECT
    id,
    PaperId,
    Title,
    Score,
    Minutes,
    (SELECT
            COUNT(*) + 1
        FROM
            tbl_user_result
        WHERE
            Score > x.Score AND Minutes > x.Minutes) AS Rank
FROM
    `tbl_user_result` as x

最佳答案

最简单的方法是使用变量:

select r.*
from (select r.*, (@rn := @rn + 1) as rank
      from tbl_user_result r cross join (select @rn := 0) vars
      order by score desc, minutes asc
     ) r;


如果没有重复项,则此方法有效。

我认为以下是您想要的查询版本:

SELECT id, PaperId, Title, Score, Minutes,
       (SELECT COUNT(*) + 1
        FROM tbl_user_result r2
        WHERE r2.Score > r.Score OR
              (r2.Score = r.Score AND r2.Minutes < r.Minutes)
       ) AS Rank
FROM  tbl_user_result r;

关于php - 如何在MySql Server中根据最高分数和最低分钟数来计算排名,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/28831300/

10-13 03:18