main.cpp:
Simple2DMatrix&Simple2DMatrix :: assign(const Simple2DMatrix&matrixB)
{
if ((numRows == matrixB.numRows)
&& (numCols == matrixB.numCols)
)
{
for (int r = 0; r < numRows; r++)
{
for (int c = 0; c < numCols; c++)
{
this->setElement(r, c, matrixB.getElement(r, c));
}
}
return (*this);
}
else
{
throw "Dimensions does not match!";
}
}
和添加为:
if ((this->numRows == matrixB.numRows)
&& (this->numCols == matrixB.numCols)
)
{
for (int r = 0; r < this->numRows; r++)
{
for (int c = 0; c < this->numCols; c++)
{
this->setElement(r, c, this->getElement(r, c) + matrixB.getElement(r, c));
}
}
return (*this);
}
else
{
throw " Dimensions does not match!";
}
因此,分配为:
{
if ((numRows == matrixB.numRows)
&& (numCols == matrixB.numCols)
)
{
for (int r = 0; r < numRows; r++)
{
for (int c = 0; c < numCols; c++)
{
this->setElement(r, c, matrixB.getElement(r, c));
}
}
return (*this);
}
else
{
throw "Dimensions does not match!";
}
}
并在operator +的标题中:
Simple2DMatrix<T> matrixTemp(matrixA.numRows, matrixA.numCols);
matrixTemp.sum(matrixA, matrixB);
return (matrixTemp);
并且对于operator =:
this->assign(matrixB);
return(*this);
非常感谢您的所有消息。
最佳答案
这是您的(运算符+)的代码:
if ((this->numRows == matrixB.numRows)
&& (this->numCols == matrixB.numCols)
)
{
for (int r = 0; r < matrixA.numRows; r++)
{
for (int c = 0; c < matrixA.numCols; c++)
{
this->setElement(r, c, matrixA.getElement(r, c) + matrixB.getElement(r, c));
} //what is matrixA?
}
return (*this); //what you want to return?? it seems you are doing B=B+C
}
else
{
throw " Dimensions does not match!";
}
实际上,您首先需要创建类的临时对象并存储
B和C在里面。
然后返回该临时变量。