regex - 在第一次匹配后使用grep(或类似方法)获取字符串

假设我在JSON中有一些文本：

{
    "key1": "value1"
    "key2": "value2"
    "key3": "value3"
    "key4": "value4"
    "key5": "value5"
}
{
    "key1": "value1"
    "key2": "value2"
    "key3": "value3"
    "key4": "value4"
    "key5": "value5"
}

我想做的是找到“ value1”，但只打印“ value5”。将有许多“ value5”，但是我只想在它前面带有“ value1”（它将是一个唯一的字符串）时打印它。我不能使用grep -Ax & -Bx

因为我不想匹配后面的行，所以我想打印字符串。

最佳答案

示例文件：

cat t
{
    "key1": "value1"
    "key2": "value2"
    "key3": "value3"
    "key4": "value4"
    "key5": "value5"
}
{
    "key1": "value6"
    "key2": "value2"
    "key3": "value3"
    "key4": "value4"
    "key5": "value5"
}

如果key5，则在key1=value6中打印数据

awk '/key1/ && /value6/ {f=1} f && /key5/ {print $NF;f=0}'
"value5"