dr——如何将json字符串发送到带有auth头的rest主机?我尝试了3种不同的方法,找到了一种可以处理匿名类型的方法。为什么我不能使用匿名类型?我需要设置一个名为“group name”的变量,连字符不是有效的c标识符。
背景
我需要发布json,但无法获得正确的正文和内容类型
函数1-用于匿名类型
内容类型和数据是正确的,但我不想使用匿名类型。我想用绳子
static void PostData(string restURLBase, string RESTUrl, string AuthToken, string postBody)
{
HttpClient client = new HttpClient();
client.BaseAddress = new Uri(restURLBase);
client.DefaultRequestHeaders.Add("Auth-Token", AuthToken);
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
// StringContent content = new StringContent(postBody);
var test1 = "data1";
var test2 = "data2";
var test3 = "data3";
var response = client.PostAsJsonAsync(RESTUrl, new { test1, test2, test3}).Result; // Blocking call!
if (!response.IsSuccessStatusCode)
{
Console.WriteLine("{0} ({1})", (int)response.StatusCode, response.ReasonPhrase);
return;
}
}
输出1
使用anonymous types+postasjsonasync时,内容类型和数据是正确的,但我不想使用匿名类型。
POST https://api.dynect.net/REST/Zone/ABCqqqqqqqqqqqqYYYYYtes3ss.com HTTP/1.1
Auth-Token: --- REDACTED -----
Accept: application/json
Content-Type: application/json; charset=utf-8
Host: api.dynect.net
Content-Length: 49
Expect: 100-continue
{"test1":"data1","test2":"data2","test3":"data3"}
函数2-不按预期工作
获取一个字符串并将其放入stringcontent对象中。这会产生更改内容类型的副作用。
static void PostData(string restURLBase, string RESTUrl, string AuthToken, string postBody)
{
HttpClient client = new HttpClient();
client.BaseAddress = new Uri(restURLBase);
client.DefaultRequestHeaders.Add("Auth-Token", AuthToken);
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
StringContent content = new StringContent(postBody);
var response = client.PostAsync(RESTUrl, content).Result; // Blocking call!
if (!response.IsSuccessStatusCode)
{
Console.WriteLine("{0} ({1})", (int)response.StatusCode, response.ReasonPhrase);
return;
}
}
输出2
使用StringContent+PostAsync时内容类型错误
POST https://api.dynect.net/REST/Zone/ABCqqqqqqqqqqqqYYYYYtes3ss.com HTTP/1.1
Auth-Token: ---- REDACTED -------
Accept: application/json // CORRECT
Content-Type: text/plain; charset=utf-8 // WRONG!!!
Host: api.dynect.net
Content-Length: 100
Expect: 100-continue
{"rdata" : ["rname" : "dynect.nfp.com", "zone" : "ABCqqqqqqqqqqqqYYYYYtes3ss.com"], "ttl" : "43200"}
// ^^ THIS IS CORRECT
函数3-不按预期工作
因为我知道
PostAsJsonAsync
正确设置了contenttype,所以让我们使用该方法。(不起作用) static void PostData(string restURLBase, string RESTUrl, string AuthToken, string postBody)
{
HttpClient client = new HttpClient();
client.BaseAddress = new Uri(restURLBase);
client.DefaultRequestHeaders.Add("Auth-Token", AuthToken);
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
StringContent content = new StringContent(postBody);
var response = client.PostAsJsonAsync(RESTUrl, content).Result; // Blocking call!
if (!response.IsSuccessStatusCode)
{
Console.WriteLine("{0} ({1})", (int)response.StatusCode, response.ReasonPhrase);
return;
}
}
输出3
内容类型正确,使用stringcontent+postsjsonasync时post body错误
POST https://api.dynect.net/REST/Zone/ABCqqqqqqqqqqqqYYYYYtes3ss.com HTTP/1.1
Auth-Token: -- REDACTED ---
Accept: application/json
Content-Type: application/json; charset=utf-8
Host: api.dynect.net
Content-Length: 74
Expect: 100-continue
{"Headers":[{"Key":"Content-Type","Value":["text/plain; charset=utf-8"]}]}
问题
我只想将json作为字符串或运行时定义的动态对象发送到服务器,使用正确的http内容类型和特殊的“auth token”头。
任何例子,如果不使用webapi,比如servicestack,或者其他任何东西都很酷。
最佳答案
/// <summary>
/// Creates a new instance of the <see cref="T:System.Net.Http.StringContent"/> class.
/// </summary>
/// <param name="content">The content used to initialize the <see cref="T:System.Net.Http.StringContent"/>.</param><param name="encoding">The encoding to use for the content.</param><param name="mediaType">The media type to use for the content.</param>
[__DynamicallyInvokable]
public StringContent(string content, Encoding encoding, string mediaType)
: base(StringContent.GetContentByteArray(content, encoding))
{
this.Headers.ContentType = new MediaTypeHeaderValue(mediaType == null ? "text/plain" : mediaType)
{
CharSet = encoding == null ? HttpContent.DefaultStringEncoding.WebName : encoding.WebName
};
}
它是stringcontent的构造函数。您应该指定适当的编码和媒体类型