一、 实验目的
掌握线性表的顺序表和链表的基本操作:建立、插入、删除、查找、合并、打印等运算。
一、 源程序
顺序表:
#include<iostream> using namespace std; #define OK 1 #define OVERFLOW -1 #define ERROR 0 #define MAXSIZE 100 int typedef Status; typedef struct//定义结构体 { int *elem; int length; }SqList; Status InitList(SqList &L)//顺序表的初始化 { L.elem = new int[MAXSIZE];//分配一个数组空间 if (!L.elem)exit(OVERFLOW); L.length = 0; return OK; } Status GetElem(SqList L, int i, int &e)//顺序表的取值 { if (i<1 || i>L.length)return ERROR; e = L.elem[i - 1];//[i-1]存储大第[i]个元素 return OK; } int LocateElem(SqList L, int e)//查找 { for (int i=0; i < L.length; i++) { if (L.elem[i] == e)return i + 1; } return 0; } Status ListInsert(SqList &L, int i, int e)//插入 { if ((i<1) || (i>L.length + 1))return ERROR; if (L.length == MAXSIZE)return ERROR; for (int j = L.length - 1; j>i - 1; j--) { L.elem[j + 1] = L.elem[j]; } L.elem[i - 1] = e; ++L.length; return OK; } Status ListDelete(SqList &L, int i)//删除 { if ((i<1) || (i>L.length))return ERROR; for (int j = i; j < L.length - 1; j++) { L.elem[j - 1] = L.elem[j];//是第i个但在数组里是第i-1个 } --L.length; return OK; } void MergeList_Sq(SqList LA, SqList LB, SqList &LC)//有序表的合并 { LC.length = LA.length + LB.length; LC.elem = new int[LC.length]; int *pc = LC.elem; int *pa = LA.elem; int *pb = LB.elem; int *pa_last = LA.elem + LA.length - 1;//指向最后一个元素 int *pb_last = LB.elem + LB.length - 1; while ((pa <= pa_last) && (pb <= pb_last)) { if ((pa <= pa_last) && (pb <= pb_last)) if (*pa <= *pb) *pc++ = *pa++; else *pc++ = *pb++; } while (pa <= pa_last)*pc++= *pa++; while (pb <= pb_last)*pc++ = *pb++; } int main() { SqList N, M; InitList(N); InitList(M); cout << "请输入第一个数组的长度" << endl;; cin >> N.length; cout << "请依次输入1到" << N.length << "的数据" << endl; for (int i = 0; i < N.length; i++) { cin >> N.elem[i]; } cout << "请输入第二个数组的长度" << endl;; cin >> M.length; cout << "请依次输入1到" << M.length << "的数据" << endl; for (int i = 0; i < M.length; i++) { cin >> M.elem[i]; } SqList A; MergeList_Sq(N, M, A); for (int i = 0; i < A.length; i++) { cout << A.elem[i] << endl; } }
约瑟夫退圈
1 #include<iostream> 2 using namespace std; 3 #define OK 1 4 #define OVERFLOW -1 5 #define ERROR 0 6 #define MAXSIZE 100 7 int typedef Status; 8 typedef struct LNode//循环链表定义 9 { 10 int data; 11 int num; 12 struct LNode *rear; 13 }LNode,*LinkList; 14 Status InitList(LinkList &L)//循环链表初始化 15 { 16 L = new LNode; 17 L->rear = L; 18 L->num = 0; 19 return OK; 20 } 21 Status GetElem(LinkList L, int i, int &e)//取值 22 { 23 LNode *p = L->rear; int j = 1; 24 while (p&&j < i)//是否要有p 25 { 26 p = p->rear; 27 ++j; 28 } 29 if (!p || j>i)return ERROR; 30 e = p->data; 31 return OK; 32 } 33 LNode *LocateElem(LinkList L, int e)//查找 34 { 35 LNode *p = L->rear; 36 while (p&&p->data != e)//是否要有p 37 { 38 p = p->rear; 39 } 40 return p; 41 } 42 Status LisrInsert(LinkList &L, int i, int e)//插入 43 { 44 LNode *p = L; int j = 0; 45 while (p && (j < i - 1)) 46 { 47 p = p->rear; 48 ++j; 49 } 50 if (!p || j>i - 1)return ERROR; 51 LNode *s = new LNode; 52 s->data = e; 53 s->rear = p->rear; 54 p->rear = s; 55 return OK; 56 } 57 Status ListDelete(LinkList &L, int i)//删除 58 { 59 LNode*p = L; int j = 0; 60 while ((p->rear) && (j < i - 1)) 61 { 62 p = p->rear; ++j; 63 } 64 if ( (j>i - 1))return ERROR; 65 LNode *q = p->rear; 66 p->rear = q->rear; 67 delete q; 68 return OK; 69 } 70 int main() 71 { 72 LinkList N; 73 LNode *t = NULL, *head; 74 InitList(N); 75 head = N->rear; 76 int n; 77 int A[MAXSIZE]; 78 cout << "请输入有几名学生:" << endl; 79 cin >> n; 80 int j = 0,i,a=0; 81 while (j < n) 82 { 83 A[a] = (a + 1); 84 cout <<"第"<<A[a]<< "人,请输入密码:" << endl; 85 cin >> i; 86 t = new LNode; 87 t->data = i; 88 t->rear = N; 89 head->rear = t; 90 head = t; 91 ++j; 92 ++a; 93 ++t->num; 94 } 95 cout << "约瑟夫环的人数以及对应密码分别是:" << endl; 96 j = 0; 97 head = N->rear; 98 while (j<n) 99 { 100 cout << "第" << A[j] << "个人,密码" << head->data << endl; 101 head = head->rear; 102 ++j; 103 } 104 cout << "请输入您想要从几开始删除:" << endl; 105 int m; cin >> m; 106 //N = N->rear; 107 ListDelete(N, m); 108 j = 0; 109 while (j<n) 110 { 111 cout << "第" << A[j] << "个人,密码" << head->data << endl; 112 head = head->rear; 113 ++j; 114 } 115 }