我的应用通过使用OpenGL着色器代码以全屏显示图像,如下所示。我在这里使用的顶点着色器是从某个地方复制的。谁能解释为什么在这里使用vTexCoord = (a_position.xy+1)/2;
?当我尝试使用vTexCoord = a_position.xy
时,我的OpenGL输出分为四个矩形,只有右上角显示图像。其他三个方面似乎都很模糊。我应该做些什么改变才能与vTexCoord = a_position.xy
一起使用?
项目中使用的一些重要功能如下所示。请检查并帮助纠正。
float[] vertices = {
// Left bottom triangle
-1f, -1f, 0f,
1f, -1f, 0f,
1f, 1f, 0f,
// Right top triangle
1f, 1f, 0f,
-1f, 1f, 0f,
-1f, -1f, 0f
};
private void CreateShaders()
{
/***********Vert Shader********************/
vertShader = GL.CreateShader(ShaderType.VertexShader);
GL.ShaderSource(vertShader, @"attribute vec3 a_position;
varying vec2 vTexCoord;
void main() {
vTexCoord = (a_position.xy+1)/2;
gl_Position = vec4(a_position, 1);
}");
GL.CompileShader(vertShader);
/***********Frag Shader ****************/
fragShader = GL.CreateShader(ShaderType.FragmentShader);
GL.ShaderSource(fragShader, @"precision highp float;
uniform sampler2D sTexture;varying vec2 vTexCoord;
void main ()
{
vec4 color= texture2D (sTexture, vTexCoord);
gl_FragColor =color;
}");
GL.CompileShader(fragShader);
}
private void InitBuffers()
{
buffer = GL.GenBuffer();
positionLocation = GL.GetAttribLocation(program, "a_position");
positionLocation1 = GL.GetUniformLocation(program, "sTexture");
GL.EnableVertexAttribArray(positionLocation);
GL.BindBuffer(BufferTarget.ArrayBuffer, buffer);
GL.BufferData(BufferTarget.ArrayBuffer, (IntPtr)(vertices.Length * sizeof(float)), vertices, BufferUsageHint.StaticDraw);
GL.VertexAttribPointer(positionLocation, 3, VertexAttribPointerType.Float, false, 0, 0);
}
public void DrawImage(int image)
{
GL.Viewport(new Rectangle(0, 0, ScreenWidth, ScreenHeight));
GL.MatrixMode(MatrixMode.Projection);
GL.PushMatrix();
GL.LoadIdentity();
//GL.Ortho(0, 1920, 0, 1080, 0, 1);
GL.MatrixMode(MatrixMode.Modelview);
GL.PushMatrix();
GL.LoadIdentity();
GL.Disable(EnableCap.Lighting);
GL.Enable(EnableCap.Texture2D);
GL.ActiveTexture(TextureUnit.Texture0);
GL.BindTexture(TextureTarget.Texture2D, image);
GL.Uniform1(positionLocation1, 0);
GL.Begin(PrimitiveType.Quads);
GL.TexCoord2(0, 1);
GL.Vertex3(0, 0, 0);
GL.TexCoord2(0, 0);
GL.Vertex3(1920, 0, 0);
GL.TexCoord2(1, 1);
GL.Vertex3(1920, 1080, 0);
GL.TexCoord2(1, 0);
GL.Vertex3(0, 1080, 0);
GL.End();
RunShaders();
GL.Disable(EnableCap.Texture2D);
GL.PopMatrix();
GL.MatrixMode(MatrixMode.Projection);
GL.PopMatrix();
GL.MatrixMode(MatrixMode.Modelview);
glControl1.SwapBuffers();
}
private void RunShaders()
{
GL.UseProgram(program);
GL.DrawArrays(PrimitiveType.Triangles, 0, vertices.Length / 3);
}
最佳答案
谁能解释为什么在这里使用vTexCoord = (a_position.xy+1)/2;
?
对于x和分量,示例中的顶点坐标在[-1,1]范围内。这与规范化的设备空间匹配。规范化的设备空间是一个从左下前(-1,-1,-1)到右上后(1、1、1)的立方体,这是“可见”的区域。该区域被映射到视口。
在您的示例中,这导致顶点坐标形成一个矩形,该矩形覆盖了整个视口。
如果纹理坐标应将整个纹理包装到四边形,则纹理坐标(u,v)必须在[0,1]范围内。 (0,0)是纹理的左下角,而(1,1)是纹理的右上角。
另见How do OpenGL texture coordinates work?
因此,a_position
的x和y分量必须从[-1,1]范围映射到[0,1]范围,以用作纹理查找的uv坐标:
u = (a_position.x + 1) / 2
v = (a_position.y + 1) / 2
我应该做些什么改变才能使用
vTexCoord = a_position.xy
?这是不可能的,但是您可以生成一个单独的纹理坐标属性,这很常见:
attribute vec3 a_position;
attribute vec2 a_texture;
varying vec2 vTexCoord;
void main() {
vTexCoord = a_texture;
gl_Position = vec4(a_position, 1);
}
float[] vertices = {
// x y z u v
// Left bottom triangle
-1f, -1f, 0f, 0f, 0f
1f, -1f, 0f, 1f, 0f
1f, 1f, 0f, 1f, 1f
// Right top triangle
1f, 1f, 0f, 1f, 1f
-1f, 1f, 0f, 0f, 1f
-1f, -1f, 0f 0f, 0f
};
buffer = GL.GenBuffer();
GL.BindBuffer(BufferTarget.ArrayBuffer, buffer);
GL.BufferData(BufferTarget.ArrayBuffer, (IntPtr)(vertices.Length * sizeof(float)), vertices, BufferUsageHint.StaticDraw);
positionLocation = GL.GetAttribLocation(program, "a_position");
tetureLocation = GL.GetAttribLocation(program, "a_texture");
GL.EnableVertexAttribArray(positionLocation);
GL.EnableVertexAttribArray(tetureLocation);
int stride = sizeof(float) * 5; // 5 because of (x, y, z, u, v)
int offsetUV = sizeof(float) * 3; // 3 because the u and v coordinates are the 4th and 5th coordinate
GL.VertexAttribPointer(positionLocation, 3, VertexAttribPointerType.Float, false, stride, 0);
GL.VertexAttribPointer(tetureLocation, 2, VertexAttribPointerType.Float, false, stride, (IntPtr)(offsetUV));