java - Hibernate-如何正确使用级联关系

我在Spring MVC应用程序中使用了休眠，并且对级联有疑问。我看到许多与此类似的问题，但没有一个可以回答我的问题。假设我有User和UserPosition对象。 User具有UserPosition的集合，并且还具有一个UserPosition作为默认位置。结构如下所示：

用户：

@OneToMany(mappedBy = "user", fetch = FetchType.LAZY)
private Collection<UserPosition> userPositionCollection;

public Collection<UserPosition> getUserPositionCollection() {
    return userPositionCollection;
}

public void setUserPositionCollection(Collection<UserPosition> collection) {
    this.userPositionCollection = collection;
}


 @OneToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinColumn(name = "default_User_Position_ID", referencedColumnName = "id")
private UserPosition defaultUserPosition;

public UserPosition getDefaultUserPosition() {
    return defaultUserPosition;
}

public void setDefaultUserPosition(UserPosition defaultUserPosition) {
    this.defaultUserPosition = defaultUserPosition;
}

UserPosition：

@JoinColumn(name = "user_id", referencedColumnName = "id")
@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
private User user;

public User getUser() {
    return user;
}

public void setUser(User user) {
    this.user = user;
}

@OneToOne(fetch = FetchType.LAZY, mappedBy = "defaultUserPosition", cascade = CascadeType.PERSIST)
private User defaultUserPosition;

public User getDefaultUserPosition() {
    return defaultUserPosition;
}

public void setDefaultUserPosition(User defaultUserPosition) {
    this.defaultUserPosition = defaultUserPosition;
}

现在，我的问题是使用级联保存相关对象的最佳实践是什么？实际上，我对这三种解决方案感到困惑：

解决方案1：

User user = new User();
//some setters and getters
UserPosition userPosition = new UserPosition();
//some setters and getters
List<UserPosition> positionList = new ArrayList<>();
positionList.add(userPosition);
user.setDefaultUserPosition(userPosition);
user.setUserPositionCollection((Collection<UserPosition>) positionList );
session.persist(user)

解决方案2：

User user = new User();
//some setters and getters
UserPosition userPosition = new UserPosition();
//some setters and getters
userPosition.setUser(user);
userPosition.setDefaultUserPosition(user);
session.persist(userPosition)

解决方案3（两个以前的解决方案的组合）：

User user = new User();
//some setters and getters
UserPosition userPosition = new UserPosition();
//some setters and getters
List<UserPosition> positionList = new ArrayList<>();
positionList.add(userPosition);
user.setDefaultUserPosition(userPosition);
user.setUserPositionCollection((Collection<UserPosition>) positionList );
userPosition.setUser(user);
userPosition.setDefaultUserPosition(user);
session.persist(user);

这对我来说很重要，请帮助我。哪种解决方案是正确的，cascade属性应该在哪里？感谢您的时间。

最佳答案

User是父实体，级联a lways propagates from Parent to Child entities。

因此，用户关联变为：

@OneToMany(mappedBy = "user",
    fetch = FetchType.LAZY,
    cascade = CascadeType.ALL,
    orphanRemoval = true)
private Collection<UserPosition> userPositionCollection;

但对于默认位置，用户将成为关联的Child：

@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "default_User_Position_ID", referencedColumnName = "id")
private UserPosition defaultUserPosition;

在UserPosition类中是另一种方法：

@JoinColumn(name = "user_id", referencedColumnName = "id")
@ManyToOne(fetch = FetchType.LAZY)
private User user;

和

@OneToOne(fetch = FetchType.LAZY,
    mappedBy = "defaultUserPosition",
    cascade = CascadeType.PERSIST)
private User defaultUserPosition;

然后，您还必须添加以下总是使双方同步的实用程序方法。这些进入User类：

public void addUserPosition(UserPosition userPosition) {
    userPositionCollection.add(userPosition);
    userPosition.setUser(this);
}

public void addDefaultUserPosition(UserPosition userPosition) {
    defaultUserPosition = userPosition;
    userPosition.setDefaultUserPosition(this);
}

持久逻辑变为：

User user = new User();
//some setters and getters
UserPosition userPosition = new UserPosition();
//some setters and getters

user.addUserPosition(userPosition);
user.setDefaultUserPosition(userPosition);

session.persist(user);