我的代码中有一个错误,例如“无法将'NSRange'类型的值(aka'_NSRange')转换为预期的参数类型'Range'(aka'范围')”,但是我不知道如何解决这个问题帮我?

我在这里发布我的代码。

NSUserDefaults.standardUserDefaults().setObject("Hey I have started using this Chat App", forKey: "Status")
            var strNumber: String = txtPhoneNumber.text!
            var myRange: NSRange = NSMakeRange(0, 2)
            var myRange1: NSRange = NSMakeRange(0, 1)
            var ran: String = strNumber.substringWithRange(myRange)  ------>  //This line error shows.
            var ran1: String = strNumber.substringWithRange(myRange1)
            if (ran == "00") || (ran == "60") || (ran == "62") || (ran == "65") || (ran == "91") || (ran == "44") {
                strNumber = strNumber.stringByReplacingOccurrencesOfString(ran, withString: "") as String
            }
            else if (ran1 == "0") {

                strNumber = strNumber.stringByReplacingOccurrencesOfString(ran1, withString: myRange1) as NSString
                //str_number = str_number.stringByReplacingOccurrencesOfString(ran1, withString: "", options: NSCaseInsensitiveSearch, range: myRange1)
            }

最佳答案

您应该将strNumber转换为NSString:var strNumber: NSString = txtPhoneNumber.text!
更多内容:NSRange to Range<String.Index>

10-06 04:47