mysql - MySQL左连接返回花费的时间太长

我有一个问题，好像我有三个表。我将国家和州的id存储在药房表中，与国家和州相关的所有详细信息分别位于tbldispensaries和tblStates中。
我正在写一个查询，以找出附近的药房半径500，以便在谷歌地图上显示标记，该查询是好的，但当我使用左连接查询，它需要太多的时间来响应。我已经尝试使用索引，但这也没有影响。所以请建议我克服这个问题。下面是我正在使用的查询：-

SELECT
    d.id AS disp,
    d.id AS the_id,
    d. NAME,
    d.address AS addr,
    d.city AS city_name,
    c.country_name AS cntry_name,
    s.state_name AS st_name,
    d.zip AS zipcode,
    d.latitude,
    d.longitude,
    (
        6371 * ACOS(
            COS(RADIANS(33.6119)) * COS(RADIANS(latitude)) * COS(
                RADIANS(longitude) - RADIANS(- 111.8906)
            ) + SIN(RADIANS(33.6119)) * SIN(RADIANS(latitude))
        )
    ) AS distance
FROM
    `tblDispensaries` d
    LEFT JOIN tblCountries c ON (c.country_id = d.country)
    LEFT JOIN tblStates s ON (s.state_id = d.state)
WHERE
    d.id IS NOT NULL
    AND d. STATUS = 1
HAVING distance < 500
LIMIT 0,60

最佳答案

这可能不是一个答案，但这是两个很大的评论。另外，我没有数据，所以我无法测试，但在这里。

SELECT
    Dispensaries.*,
    c.country_name AS cntry_name,
    s.state_name AS st_name
FROM (
  SELECT
      d.id AS disp,
      d.id AS the_id,
      d. NAME,
      d.address AS addr,
      d.city AS city_name,
      d.zip AS zipcode,
      d.latitude,
      d.longitude,
      (
          6371 * ACOS(
              COS(RADIANS(33.6119)) * COS(RADIANS(latitude)) * COS(
                  RADIANS(longitude) - RADIANS(- 111.8906)
              ) + SIN(RADIANS(33.6119)) * SIN(RADIANS(latitude))
          )
      ) AS distance
  FROM
      `tblDispensaries` d
  WHERE
      d.id IS NOT NULL
      AND d. STATUS = 1
  HAVING distance < 500
  LIMIT 0,60
) as Dispensaries
LEFT JOIN tblCountries c ON (c.country_id = Dispensaries.country)
LEFT JOIN tblStates s ON (s.state_id = Dispensaries.state)

我想获取结果和使用aJOIN会更快。