我有针对客户的每个请求返回给客户的课程响应,我的响应是:
public class Response<T> extends Request{
private ResponseType responseType;
private String message;
private ArrayList<T> result;
private int activationCode;
.
.
.
}
在我的服务器端,我有返回响应的方法,其中包含结果与InstagramUser的arraylist
我的方法:
public Response getUserByUserName(@RequestBody List<Request> requests){
.
.
.
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
try {
String searchResponse = restTemplate.getForObject(uri, String.class);
JSONObject rawObject = new JSONObject(searchResponse);
JSONArray searchResults = rawObject.getJSONArray("data");
ArrayList<InstagramUser> users = new ArrayList<InstagramUser>();
for (int i = 0; i < searchResults.length(); i++) {
JSONObject result = searchResults.getJSONObject(i);
users.add(new InstagramUser(result, AccessToken.getTokenString()));
}
response = new Response(requests.get(0).getUserId(), ResponseType.success, "users find successfully on: " + new Date().toString());
response.setResult(users);
.
.
.
return response;
}
和我的InstagramUser:
public class InstagramUser extends InstagramModel {
protected long id;
protected String userName;
protected String fullName;
protected String profilePictureURI;
protected String bio;
protected String website;
protected int mediaCount = -1;
protected int followerCount = -1;
protected int followingCount = -1;
...
}
但是在客户端,当我从服务器获取响应时,我的结果是由InstagramUser的ArrayList插入的LinkedHashMap的ArrayList:
restTemplate.postForObject(URL + conditions, params,Response.class);
这是我从服务器调用此方法的json响应:
{
"id": 6151638910251304448,
"userId": 2,
"instagramId": null,
"searchId": null,
"mediaId": null,
"phoneNumber": null,
"name": null,
"date": 1466665008687,
"responseType": "success",
"message": "users find successfully on: Thu Jun 23 11:26:48 IRDT 2016",
"result": [
{
"id": 110000004535,
"userName": "______etabdar",
"fullName": "________dar",
"profilePictureURI": "https://igcdn-photos-h-a.akamaihd.net/hphotos-ak-xap1/t51.2885-19/s150x150/13183XXXXXXXX0231_1584363729_a.jpg",
"bio": "🎓 XXXXX 90",
"website": "",
"mediaCount": -1,
"followerCount": -1,
"followingCount": -1
}
],
"activationCode": 0
}
我怎样才能解决这个问题?
最佳答案
您将必须使用参数化类型引用。仅适用于其余模板交换方法。
List<YourObjectType>> res = template.exchange(
rootUrl,
HttpMethod.POST,
null,
new ParameterizedTypeReference<List<YourObjectType>>() {});
根据您的输入调整参数。